D. 24x + 16y is your answer
Answer:
45
Step-by-step explanation:
So you have the equation:
(3x - 5) ^(x) - 19
and the value x = 3,
so just substitute in and simplify:
(3*3 - 5) ^ (3) - 19
(9 - 5)^(3) - 19
(4)^(3) - 19
64 - 19
45
6/x = x-1
Multiply x by both sides
6= x(x-1)
Set x and x-1 equal to 6
x = 6, x = 1+6 = 7
You can do 8 + 8 = 16 then minus 1 cuz thats how much you added
Answer:
a) weight of the car = 2816,1 lbs
b) 2773 lbs
Step-by-step explanation:
The equilibrium force is 490 lbs. That force keep the car at rest, then
∑ Fy = 0 and ∑Fx = 0
Forces acting on the car:
The external force 490 lbs
weight of the car uknown
Normal force
sin∠10° = 0,174
cos∠10° = 0.985
∑Fx = 0 mg*sin10°- 490 = 0 ∑Fy = 0 mg*cos10° - N = 0
mg*0,174= 490
mg = 490 / 0,174
mg = 2816,1 lbs
weight of the car = 2816,1 lbs
The Normal force
mg*cos10° - N = 0 2816,1 * 0,985 = N
N = 2773 lbs
Then equal force in magnitude and in opposite direction will car exets on the driveway
