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Neko [114]
3 years ago
13

Book A: 120 pages Book B: 170 pages Book C: 90 pages Kevin and Dashawn were both assigned reading from books A, B, and C above.

Kevin completed 40% of Book A, 30% of Book B, and 10% of Book C. Dashawn completed 50% of Book A, 20% of Book B, and 30% of Book C. How many pages did each student read?
Mathematics
2 answers:
Delvig [45]3 years ago
6 0

Answer:

Kevin:

Book A------> 40% × 120

= 48 pages

Book B------> 30% × 170

= 51 pages

Book C------> 10% × 90

= 9 pages

Total------> 48+51+9

= 108 pages

Dashawn:

Book A------> 50% × 120

= 60 pages

Book B------> 20% × 170

= 34 pages

Book C------> 30% × 90

= 27 pages

Total------> 60+34+27

= 121 pages

Luda [366]3 years ago
4 0

Kevin:

Book A------> 40% × 120

= 48 pages

Book B------> 30% × 170

= 51 pages

Book C------> 10% × 90

= 9 pages

Total------> 48+51+9

= 108 pages

Dashawn:

Book A------> 50% × 120

= 60 pages

Book B------> 20% × 170

= 34 pages

Book C------> 30% × 90

= 27 pages

Total------> 60+34+27

= 121 pages

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I believe the answer is C. 2.43

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3 years ago
Bharat types 20 words/min. How many words can he type in each length of time? a) 5 min b) 30 min c) 23 min
e-lub [12.9K]

Bharat can type words in lengths of time as 100 words, 600 words, and 460 words in 5 minutes, 30 minutes, and 23 minutes respectively.

<h3>What are Arithmetic operations?</h3>

Arithmetic operations can also be specified by subtracting, dividing, and multiplying built-in functions.

* Multiplication operation: Multiplies values on either side of the operator

For example 12×2 = 24

Bharat types 20 words per minute which are given in the question.

To determine the number of words can he type in each length of time

We have to multiply the time by his typing speed.

The number of words that can be typed by Bharat in 5 minutes :

⇒ 20 × 5

⇒ 100

The number of words that can be typed by Bharat in 30 minutes :

⇒ 20 × 30

⇒ 600

The number of words that can be typed by Bharat in 23 minutes :

⇒ 20 × 23

⇒ 460

Therefore, He can type words in lengths of time as 100 words, 600 words, and 460 words in 5 minutes, 30 minutes, and 23 minutes respectively.

Learn more about Arithmetic operations here:

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3 0
1 year ago
Phones-R-Us charges $16.95 per month and $0.05 per text message. Awesome Wireless charges $22.95 per
Dima020 [189]

Answer:

S \leq 200

Step-by-step explanation:

Given

Phone R-Us= $16.95 + $0.05 per SMS

Awesome Wireless = $22.95 + $0.02 per SMS

Required

Determine the number of SMS such that Awesome Wireless is greater or equal to Phone R-Us

Represent the SMS with S

For Phone R-Us, we have:

SMS = 16.95 + 0.05S

For Awesome Wireless, we have:

SMS = 22.95 + 0.02S

For Awesome Wireless is greater or equal to Phone R-Us, we have:

22.95 + 0.02S \geq 16.95 + 0.05S

Collect Like Terms

0.02S - 0.05S \geq 16.95 - 22.95

-0.03S \geq -6

Solve for S

\frac{-0.03S}{-0.03} \geq \frac{-6}{-0.03}

S \leq 200

<em>Hence: for Awesome Wireless to cost more or equal to Phone R-Us, the number of SMS must not exceed 200</em>

4 0
3 years ago
Which of the equations below could be the equation of this parabola?
nirvana33 [79]

Answer:

 y=-4x^2  is the equation of this parabola.

Step-by-step explanation:

Let us consider the equation

y=-4x^2

\mathrm{Domain\:of\:}\:-4x^2\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

\mathrm{Range\:of\:}-4x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\le \:0\:\\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:0]\end{bmatrix}

\mathrm{Axis\:interception\:points\:of}\:-4x^2:\quad \mathrm{X\:Intercepts}:\:\left(0,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:0\right)

As

\mathrm{The\:vertex\:of\:an\:up-down\:facing\:parabola\:of\:the\:form}\:y=a\left(x-m\right)\left(x-n\right)

\mathrm{is\:the\:average\:of\:the\:zeros}\:x_v=\frac{m+n}{2}

y=-4x^2

\mathrm{The\:parabola\:params\:are:}

a=-4,\:m=0,\:n=0

x_v=\frac{m+n}{2}

x_v=\frac{0+0}{2}

x_v=0

\mathrm{Plug\:in}\:\:x_v=0\:\mathrm{to\:find\:the}\:y_v\:\mathrm{value}

y_v=-4\cdot \:0^2

y_v=0

Therefore, the parabola vertex is

\left(0,\:0\right)

\mathrm{If}\:a

\mathrm{If}\:a>0,\:\mathrm{then\:the\:vertex\:is\:a\:minimum\:value}

a=-4

\mathrm{Maximum}\space\left(0,\:0\right)

so,

\mathrm{Vertex\:of}\:-4x^2:\quad \mathrm{Maximum}\space\left(0,\:0\right)

Therefore,  y=-4x^2  is the equation of this parabola. The graph is also attached.

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3 years ago
Data set is normally distributed with a mean of 27 and a standard deviation of 3.5. Find the Z-score for a value of 25, to the n
Svetradugi [14.3K]

What is the standard deviation of the data set?

6, 4, 9, 5, 5, 4, 5

Round the answer to the tenths place.What is the standard deviation of the data set?

6, 4, 9, 5, 5, 4, 5

Round the answer to the tenths place.

Step-by-step explanation:

ERFSDFNJKOODSJNFIODSJIFJDSIOFDSF

3 0
2 years ago
Read 2 more answers
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