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Andre45 [30]
3 years ago
9

ASSIGNMENT

Mathematics
1 answer:
wel3 years ago
8 0

Answer:

H

Step-by-step explanation:

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Pls show work thank you!!!
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2 years ago
The claim is that the proportion of adults who smoked a cigarette in the past week is less than 0.30​, and the sample statistics
IrinaK [193]

Answer: 0.84

Step-by-step explanation:

let p be the population proportion of adults who smoked a cigarette in the past week.

As per given , we have

H_a: p

Sample size : n= 1491

The sample proportion of adults smoked a cigarette= \hat{p}=\dfrac{x}{n}=\dfrac{462}{1491}=0.30985915493\approx0.31

The test statistic for proportion is given by :-

z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

Substitute all the values , we get

z=\dfrac{0.31-0.30}{\sqrt{\dfrac{0.30(1-0.30)}{1491}}}\\\\=\dfrac{0.01}{\sqrt{0.000141}}\\\\=\dfrac{0.01}{0.011874342087}=0.84261497731\approx0.84

Hence, the value of the test statistic = 0.84

6 0
3 years ago
Wh/o wan/t to ch/at?
Inessa05 [86]
Me sure ok what vtofneongorco
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3 years ago
There are 1800 gym members in total, 3/4 are aged 25-59, 1/5 are over 60 and the remainder are under 25, how many members are un
siniylev [52]
If x is the number of members under 25, then we have

1800=\dfrac34\cdot1800+\dfrac15\cdot1800+x\implies x=90
8 0
3 years ago
How to solve 1.25 x 10^-4
enyata [817]

Answer:

0.000125x

Step-by-step explanation:

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