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Setler79 [48]
4 years ago
10

Find the value of z such that the area between -z and z is 85%

Mathematics
1 answer:
Marta_Voda [28]4 years ago
8 0

We want the integral of the standard normal from -z to z to be 0.85.  Let's look at some standard normal tables and pick the right one.

It's easy to find the Erf one, which is the integral of the unit normal from 0 to z.  That will be exactly half of the integral from -z to z.  So we look for the z value corresponding to a probability of 0.425 in that table and find

z = 1.44

Answer: 1.44

[figure from Wikipedia]

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Arrange the geometric series from least to greatest based on the value of their sums.
son4ous [18]

Answer:

80 < 93 < 121 < 127

Step-by-step explanation:

For a geometric series,

\sum_{t=1}^{n}a(r)^{t-1}

Formula to be used,

Sum of t terms of a geometric series = \frac{a(r^t-1)}{r-1}

Here t = number of terms

a = first term

r = common ratio

1). \sum_{t=1}^{5}3(2)^{t-1}

   First term of this series 'a' = 3

   Common ratio 'r' = 2

   Number of terms 't' = 5

   Therefore, sum of 5 terms of the series = \frac{3(2^5-1)}{(2-1)}

                                                                      = 93

2). \sum_{t=1}^{7}(2)^{t-1}

   First term 'a' = 1

   Common ratio 'r' = 2

   Number of terms 't' = 7

   Sum of 7 terms of this series = \frac{1(2^7-1)}{(2-1)}

                                                    = 127

3). \sum_{t=1}^{5}(3)^{t-1}

    First term 'a' = 1

    Common ratio 'r' = 3

    Number of terms 't' = 5

   Therefore, sum of 5 terms = \frac{1(3^5-1)}{3-1}

                                                 = 121

4). \sum_{t=1}^{4}2(3)^{t-1}

    First term 'a' = 2

    Common ratio 'r' = 3

    Number of terms 't' = 4

    Therefore, sum of 4 terms of the series = \frac{2(3^4-1)}{3-1}

                                                                       = 80

    80 < 93 < 121 < 127 will be the answer.

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3 years ago
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Answer:45,311

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I hope this is good enough:

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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free 100 points How do the 6s in 0.96 and 93.601 compare? The value of the 6 in 0.96 is 100 times the value of the 6 in 93.601.
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Answer:

Answer is below

Step-by-step explanation:

The value of the 6 in 0.96 is 1/10 the value of the 6 in 93.601. This is because the 6 in 0.96 is in the hundredths place, compared to the 6 in 93.601 which is in the tenths place.

If this answer is correct, please make me Brainliest!

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