Question

What is the domain and range of the square root of x+3-1?

Answer 1

Answer:

$\large\boxed{\text{The domain:}\ x\geq-3\to x\in[-3,\ \infty)}\\\boxed{\text{The range:}\ y\geq-1\to y\in[-1,\ \infty)}$

Step-by-step explanation:

$y=\sqrt{x+3}-1\\\\The\ domain:\\\\x+3\geq0\qquad\text{subtract 3 from both sides}\\\\x\geq-3\to x\in[-3,\ \infty)\\\\The\ range:\\\\\sqrt{x+3}\geq0\qquad\text{subtract 1 from both sides}\\\\\sqrt{x+3}-1\geq-1\\\\y\geq-1\to y\in[-1,\ \infty)$