7.714, if you divide 432 by 56, you get 7.714
An easy way to do this is by using the simplest equations you can:
x + y and x - y
(3, 5) is (x, y). all you have to do is plug those into your equations and get a result, so:
x + y = 8
(because 3 + 5 = 8)
x - y = -2
(because 3 - 5 = -2)
and those can serve as your system of equations.
you can check it by solving by substitution:
x - y = -2
x + y = 8
solve one of the equations for a single variable:
x = y - 2
plug it into the second equation:
(y - 2) + y = 8
y - 2 + y = 8
2y - 2 = 8
2y = 10
y = 5
then plug that result back into the equation:
x + y = 8
x + 5 = 8
x = 3
B = 16
x^2 + 16x + 64 can be factored down to (x + 8)^2.
1 one change I don't know how but change
<h3>
Answer:</h3>
1/17 or 0.0588 (without replacement)
<h3>
Step-by-step explanation:</h3>
To answer this question we need to know the following about a deck of cards
- A deck of cards contains 4 of each card (4 Aces, 4 Kings, 4 Queens, etc.)
- Also there are 4 suits (Clubs, Hearts, Diamonds, and Spades).
- Additionally, there are 13 cards in each suit (Clubs/Spades are black, Hearts/Diamonds are red)
.
In this case, we are required to determine the probability of choosing two diamonds.
- There are 13 diamonds in the deck.
- Assuming, the cards were chosen without replacement;
P(Both cards are diamonds) = P(first card is diamond) × P(second card is diamond)
P(First card is diamond) = 13/52
If there was no replacement, then after picking the first diamond card, there are 12 diamond cards remaining and a total of 51 cards remaining in the deck.
Therefore;
P(Second card is diamond) = 12/51
Thus;
P(Both cards are diamonds) = 13/52 × 12/51
= 156/2652
= 1/17 or 0.0588
Hence, the probability of choosing two diamonds at random (without replacement) is 1/17 or 0.0588.
