Question

Find the perimeter of quadrilateral ABCD. Round to the nearest tenth.

Answer 1

Answer:

Perimeter = 13.5 units

Step-by-step explanation:

Coordinates of A → (1, 2)

Coordinates of B → (2, 5)

Coordinates of C → (5, 7)

Coordinates of D → (4, 4)

Length of AB = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1}})^2}$

                      = $\sqrt{(2-1)^2+(5-2)^2}=\sqrt{10}$ units

Length of BC = $\sqrt{(5-2)^2+(7-5)^2}$

                      = $\sqrt{13}$ units

Length of CD = $\sqrt{(5-4)^2+(7-4)^2}=\sqrt{10}$ units

Length of AC = $\sqrt{(4-1)^2+(4-2)^2}=\sqrt{13}$ units

Perimeter of the quadrilateral = $2(\sqrt{10}+\sqrt{13})$

                                                  = 2(3.16 + 3.61)

                                                  = 13.54

                                                  ≈ 13.5 units

Perimeter of the quadrilateral ABCD is 13.5 units