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bazaltina [42]
3 years ago
14

3.2 is ten times as much as what

Mathematics
2 answers:
Nezavi [6.7K]3 years ago
6 0
.32 because you have to take away the ones place for an accurate answer!

;)
horrorfan [7]3 years ago
6 0
This isn't an answer but I have the same background!And it's 0.32
You might be interested in
Simplify 15-7 2 using order of operations
Butoxors [25]
16 is the solution to this if you're multiplying the 2
5 0
3 years ago
If you could please help, what is the missing answer?<br><br> Thank you to anyone who helps out!
ICE Princess25 [194]

Answer:

48

Step-by-step explanation:

let s be the snowman, g be the girl, and t be the christmas tree

2s+g=24

2t+2ts=132

3t+2g=26

subtract 2 times the first equation from the third one to get

3t-4s=-22

from the second equation we can deduce

2t(1+s)=132

t(1+s)=66

t=66/(1+s)

Substitute:

3(66)/(1+s)-4s=-22

3(66)/(1+s)=4s-22

3(66)=(4s-22)(1+s)

3(66)=-18s+4s^2-22

4s^2-18s-220=0

using the quadratic formula, we get s = 10, s = -5.5.

2(10)+g=24

g=4

2t(1+10)=132

2t=12

t=6

So 2s+t*g= 20+6*4=48

you would get a different solution for the negative s, but since snowmen cannot be negative, 48 is the answe.r

8 0
3 years ago
#30 PLEASE HELP!! DUE SOON :(
Varvara68 [4.7K]

Answer:

Step-by-step explanation:

Use this to help; starting out, this is coordinate plain, NOT TO SCALE.

Use the coordinates to figure out midpoints. If you don't know how to, look up the calculation method for it.

Sorry I couldn't help out more, gotta get back to essay.

6 0
3 years ago
A university researcher wants to estimate the mean number of novels that seniors read during their time in college. An exit surv
lys-0071 [83]

Answer:

Population mean = 7 ± 2.306 × \frac{2.29}{\sqrt{9} }

Step-by-step explanation:

Given - A university researcher wants to estimate the mean number

            of  novels that seniors read during their time in college. An exit

            survey was conducted with a random sample of 9 seniors. The

            sample mean was 7 novels with standard deviation 2.29 novels.

To find - Assuming that all conditions for conducting inference have

              been met, which of the following is a 94.645% confidence

              interval for the population mean number of novels read by

              all seniors?

Proof -

Given that,

Mean ,x⁻ = 7

Standard deviation, s = 2.29

Size, n = 9

Now,

Degrees of freedom = df

                                = n - 1

                                = 9 - 1

                                = 8

⇒Degrees of freedom = 8

Now,

At 94.645% confidence level

α = 1 - 94.645%

   =1 - 0.94645

  =0.05355 ≈ 0.05

⇒α = 0.5

Now,

\frac{\alpha}{2} = \frac{0.05}{2}

  = 0.025

Then,

t_{\frac{\alpha}{2}, df }  = 2.306

∴ we get

Population mean = x⁻ ± t_{\frac{\alpha}{2}, df } ×\frac{s}{\sqrt{n} }

                           = 7 ± 2.306 × \frac{2.29}{\sqrt{9} }

⇒Population mean = 7 ± 2.306 × \frac{2.29}{\sqrt{9} }

3 0
4 years ago
Read 2 more answers
Plot the image of quadrilateral ABCD under a reflection across the x-axis.
OleMash [197]

Answer:

wsg??

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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