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Oduvanchick [21]
3 years ago
7

Consider the following function:y=1/(x+5)+2

Mathematics
2 answers:
Galina-37 [17]3 years ago
8 0

Answer:

Step-by-step explanation:

Starting with the parent function, x was replaced by (x + 5), indicating that the graph of the new function is that of the old function shifted 5 units to the LEFT.  That +2 shifts this result UP by 2 units.

juin [17]3 years ago
3 0

Answer:

It is shifted left 5 units and up 2 units from the parent function.

Answer B on edge

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The radius of a circle is 20 cm. Find its area in terms of π π.
natulia [17]

Answer:

A = 400\pi cm^2

Step-by-step explanation:

Area of a circle is:

A = πr²

We are given a radius of 20 cm.

A = πr²

A = π(20)²

A = π400

<em>A = 400πcm²</em>

Hope this helps.

4 0
3 years ago
Estimate the area of Alberta in square miles. Show your reasoning
ella [17]

Answer:  About 278,250\ mi^2

Step-by-step explanation:

The missing figure is attached.

Notice in the first picture that Alberta has a complex shape.

You can calculate the area of a complex shape by decomposing it into polygons whose areas can be calculated easily.

Observe the second picture. Notice that it can be descompose into two polygons: A trapezoid and a rectangle.

The area of the trapezoid  can be calcualted with the formula:

A_t=\frac{h}{2}(B+b)

Where "h" is the height, "B" is the long base and "b" is short base.

And the area of the rectangle can be found with the formula:

 A_r=lw

Wkere "l" is the lenght and "w" is the width.

Then, the apprximate area of Alberta is:

A=\frac{h}{2}(B+b)+lw

Substituting vallues, you get:

A=(\frac{(410\ mi-180\ mi)}{2})(760\ mi+470\ mi)+(180\ mi)(760\ im)\\\\A=141,450\ mi^2+136,800\ mi^2\\\\A=278,250\ mi^2

Therefore, the area of of Alberta is about 278,250\ mi^2.

5 0
3 years ago
In a cohort of 35 graduating students, there are three different prizes to be awarded. If no student can receive more than one p
sweet [91]

We have been given in a cohort of 35 graduating students, there are three different prizes to be awarded. We are asked that in how many different ways could the prizes be awarded, if no student can receive more than one prize.

To solve this problem we will use permutations.

_{r}^{n}\textrm{P}={_{3}^{35}\textrm{P}}

We know that formula for permutations is given as

_{r}^{n}\textrm{P}=\frac{n!}{(n-r)!}

On substituting the given values in the formula we get,

{_{3}^{35}\textrm{P}}=\frac{35!}{(35-3)!}=\frac{35!}{32!}

=\frac{35\cdot 34\cdot 33\cdot 32!}{32!}\\&#10;\\&#10;=35\cdot 34\cdot 33=39270

Therefore, there are 39270 ways in which prizes can be awarded.


6 0
3 years ago
PLEASE HELP URGENT!!!!
Setler [38]

Answer:

A hope this helps

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
You try! Which of the following boxes is filled in
Verizon [17]

Answer:

The first one.

Step-by-step explanation:

The first one.  7x² times 2x = 14x³

3 0
3 years ago
Read 2 more answers
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