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inna [77]
3 years ago
12

1. a) Explain the possible pathways a water molecule can take as it makes its way through the

Biology
2 answers:
REY [17]3 years ago
4 0

Answer:

Precipitation:

At the right atmospheric conditions of pressure and temperature the small droplets of water forms the large droplets in the cloud and falls down to earth, this phenomenon or process known as precipitation.

Runoff:

As the water falls due to precipitation termed as rainfall which usually streams down the earth to various water bodies such as lakes, rivers and oceans. This is known as runoff.

Infiltration:

the movement or going back under the surface of the earth or ground is known as infiltration and it is necessary to maintain ground level of water.

Transpiration:

The roots of the plants absorbs the water that went through the soil which move to various part of the plant body from their it evaporates and move to the atmosphere. It is known as transpiration.

Evaporation:

This process takes place when water converts from the liquid state to the gaseous state.

Condensation:

Condensation is takes place when conversion of gaseous state into the liquid state.

Precipitation again and cycle keep moving.

ahrayia [7]3 years ago
3 0

Answer:

Water always takes the path of least resistance. You ask to much for just 4 pts. All the terms you want outlined can simply be found in a DICTIONARY.

Explanation:

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Why does a metal sink in water but the same size block of wood float
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You and your colleagues are constructing a pedigree for a boy with cystic fibrosis. The individual’s younger brother has also be
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<em>The correct option is B) Both would be represented as completely shaded squares.</em>

Explanation:

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In a pedigree, males are usually drawn as squares. A male who is carrying a disorder or a particular phenotype under study is represented by shading the square. A male who is a carrier for the trait under study is represented by lines on the square. Hence, option B is correct.

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4 years ago
CREATING PUNNETT SQUARES FOR THE FISHER FAMILY There are six people in the Fisher family. Olivia and Marcus are the parents. The
trasher [3.6K]
Really, there are multiple questions all rolled into one.I will try to answer them patiently and systematically.
First summarize data.
A. Neither Olivia nor Marcus have freckles (recessive, ff)
B. Both are heterozygous for the hairline trait (dominant Ww)
C. Neither Marcus nor Olivia can roll their tongues (rr).
D. All four children have dimples (dominant Dx)
E. Both Olivia and Marcus are EE (unattached earlobe trait).
F. Marcus can not detect the bitter taste (pp for PTC gene)Olivia has been found to be able to detect the bitter taste, but she is heterozygous for the trait. (Pp for PTC gene)

A. Freckles, F (Dominant)
"Neither Olivia nor Marcus have freckles" =>
both have genotype ff.
None of the children have freckles (i.e. P(F)=0% for freckles in all children)

B. Widow's Peak, W (dominant)
"Both are heterozygous for the hairline trait"
So both have genotype Ww.
Punnett square
       W    w 
W WW Ww
w Ww   ww
Since W is a dominant trait, only ww (25%) will have straight hairline, 75% will inherit the widow's peak. 
50% of the children will be homozygous (Ww).

C. Rolling tongues, R  (dominant)
"Neither Marcus nor Olivia can roll their tongues" 
means that both are homozygous recessive, with genotype rr.As in freckles, all children will have genotype rr, so none of them will roll their tongues. 
None will be heterozygous.  The whole family's genotype is rr.


D. Dimples, D (dominant)
"D. All four children have dimples"
implies that all children have genotype DD or Dd.
It is likely that at least one parent has genotype DD in order to have 100% of children have DD or Dd.Here are some possibilities

Case 1: DD + DD (both homoozygous dominant)
     D   D   
D DD DD
D DD DD
Phenotype: 100% have dimples

Case 2: DD + Dd (one homoozygous dominant, and other heterozygous) 
     D  d
D DD Dd
D DD Dd
Phenotype: 100% have dimples

Case 3: DD + dd (one homoozygous dominant, and other homozygous recessive) 
    D    D
D DD DD
d Dd Dd
Phenotype: 100% have dimples

Case 4: Dd + Dd (both heterozygous) 
      D  d
D DD Dd
d Dd dd
Phenotype: 75% have dimples, 25 do not.Note: all 4 children could have dimples, with probability 31.6%

Case 5: Dd + dd (Heterozygous + homozygous recessive)
     D  d
d Dd dd
d Dd dd
Phenotype: 50% have dimples, 50 do not.Note: All four children could have dimples, with probability 6.25%.

Case 6: dd + dd (Both homozygous recessive)
   D   d
d dd dd
d dd dd
Phenotype: all children have no dimples.
Conclusion:Likely genotypes of parents: DD+DD, DD+Dd, DD+dd
Possible genotypes of parents: Dd+Dd, Dd+dd
Impossible genotype of parents: dd+dd
Therefore we know with certainty that at least one of the parents has dimples.

E. Unattached Earlobe trait, E (dominant)
"Both Olivia and Marcus are EE"
(i.e. unattached earlobe trait).
This means that the whole family will have genotype EE, i.e. all are homozygous dominant, and have unattached earlobes.

F. Bitter taste, P  (incomplete dominance)
"Marcus can not detect the bitter taste (pp for PTC gene)
Olivia has been found to be able to detect the bitter taste, but she is heterozygous for the trait. (Pp)"
     P   p
p Pp pp
p Pp pp
Probability for each single child being able to taste the ptc paper is 1/2.
Probability for all children being able to taste the ptc paper is (1/2)^4=1/16.
If Violet cannot taste the ptc paper, her genotype is pp.
We do not know for sure how many of the children can taste the ptc paper. 
The most like situation is only half of them can taste, so do the parents.  Therefore, half of the family can taste the ptc paper.


Finally, as to "please answer it correctly", I believe I did.  :)


6 0
3 years ago
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