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dimaraw [331]
3 years ago
5

Trey mechanic will fix Trey's car at a rate of $20 per hour, plus $400 for the cost of a part. Trey's neighbor already has the n

eeded part and will fix the car for only $70 per hour. For how many hours will the cost of having the car fixed by either person be the same?
Mathematics
1 answer:
makvit [3.9K]3 years ago
8 0

Answer:

8 hours.

Step-by-step explanation:

let x represent number of hours.

We have been given that Trey mechanic will fix Trey's car at a rate of $20 per hour, plus $400 for the cost of a part.

So total cost of repairing a car for x hours by Trey mechanic would be 20x+400.

We are also told that the neighbor has the needed part and will fix the car for only $70 per hour. So total cost of repairing a car for x hours by neighbor would be 70x.

To find the number of hours, when the cost of fixing the car by either person will be equal, we need to equate both expressions as:

70x=20x+400

Let us solve for x.

70x-20x=20x-20x+400

50x=400

x=\frac{400}{50}

x=8

Therefore, after 8 hours the cost of having the car fixed by either person will be the same.

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