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Vikentia [17]
3 years ago
13

How would i solve these?

Mathematics
1 answer:
olchik [2.2K]3 years ago
8 0
So for a, the y-intercept would be positive 2 (first equation) and the slope would be 3/1. When you graph the y-intercept, which you have to do first, you can use the slope to figure out the line. The same thing would happen with the second equation. -8 is the y-intercept and -2/1 is the slope. (Negative slope would be, in this case, down 2 right 1)
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What is the difference between exponent form and expanded form (repeated multiplication)?
Inga [223]
Expanded FormExpanded form refers to a base and an exponent written as repeated multiplication. ExponentExponents are used to describe the number of times that a term is multiplied by itself. ExpressionAn expression is a mathematical phrase containing variables, operations and/or numbers.
5 0
3 years ago
For every 3 wrapped packages Mary uses 1/2 roll of wrapping paper how many packages can she wrap with 2 1/2 rolls of wrapping pa
8_murik_8 [283]

Answer:

15 packages

Step-by-step explanation:

Set up a proportion, where x is the number of packages she can wrap with 2.5 rolls of wrapping paper:

\frac{3}{0.5} = \frac{x}{2.5}

Cross multiply and solve for x:

0.5x = 7.5

x = 15

So, with 2.5 rolls of wrapping paper, she can wrap 15 packages

8 0
2 years ago
Assume that they all agree on the sample size and the sample mean use the pairs below to select the team that has the smallest s
Archy [21]

Step-by-step explanation:

A.Confidence Level: 99.7%; Confidence Interval: 42 to 48 

B.Confidence Level: 95%; Confidence Interval: 43 to 47

 C.Confidence Level: 68%; Confidence Interval: 44 to 46 

D.Confidence Level: 95%; Confidence Interval: 44 to 46

6 0
2 years ago
Which of the following is the solution to | x -12 | < 15
KiRa [710]
Hello,
Answer D    -3<x<27
Indeed:
1)
if x-12≥0 then x≥12 and
|x-12|=x-12x-12<15 → x<27
so 12≤x<27
2) if x-12<0 then
x<12 and|x-12|=-(x-12)<15
-x+12<15-x<3 → x>-3
So -3<x<12
Thus -3<x<12  U 12≤x<27 ⇔ -3<x<27

7 0
2 years ago
2.06. In a study to estimate the proportion of residents in a certain city and its suburbs who favor the construction of a nucle
DaniilM [7]

Answer:

z=\frac{0.74-0.56}{\sqrt{0.64(1-0.64)(\frac{1}{100}+\frac{1}{125})}}=2.795  

p_v =2*P(Z>2.795)= 0.005  

So if we compare the p value and using any significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the proportions are different at 5% of significance.  

Step-by-step explanation:

Data given and notation  

X_{1}=74 represent the number of residents in a certain city and its suburbs who favor the construction of a nuclear power plant

X_{2}=70 represent the number of people suburban residents are in favor

n_{1}=100 sample 1 selected

n_{2}=125 sample 2 selected

p_{1}=\frac{74}{100}=0.74 represent the proportion of residents in a certain city and its suburbs who favor the construction of a nuclear power plant

p_{2}=\frac{70}{125}=0.56 represent the proportion of suburban residents are in favor

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the proportions are different, the system of hypothesis would be:  

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{74+70}{100+125}=0.64

Calculate the statistic

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.74-0.56}{\sqrt{0.64(1-0.64)(\frac{1}{100}+\frac{1}{125})}}=2.795  

Statistical decision

The significance level provided is \alpha=0.05 ,and we can calculate the p value for this test.  

Since is a two tailed test the p value would be:  

p_v =2*P(Z>2.795)= 0.005  

So if we compare the p value and using any significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the proportions are different at 5% of significance.  

5 0
3 years ago
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