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ivann1987 [24]
3 years ago
6

Please Do Solve it guys...

Computers and Technology
1 answer:
asambeis [7]3 years ago
5 0

Answer:

Explanation:

I assume the question is the number 4, because there is no question about the types of computer, in this case, there are different types of HTML tags, for example:

<u>Basic tags</u>

<!DOCTYPE> Defines the document type

<html> Defines an HTML document

<head> Defines information about the document

<u>Formatting</u>

<address> Defines contact information for the author

<code> Defines a piece of computer code

<strong> Defines important text

<u>Forms and Input</u>

<form> Defines an HTML form for user input

<input> Defines an input control

<button> Defines a clickable button

<output> Defines the result of a calculation

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katen-ka-za [31]
A DNS record <span>is responsible for resolving an IP to a domain name.
</span>The term DNS record denotes a database record, stored on DNS servers used to map a URL to an IP address. 
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3 0
3 years ago
A _____ is an electronic path over which data can travel.
vazorg [7]
A bus is an electrical path which data travels between the different components in an electronic device.                                                                      
5 0
4 years ago
Consider the following high-level recursive procedure: long long int flong long int n, long long int k long long int b b k+2; if
Stolb23 [73]

Answer:

f(long long, long long):

push rbp

mov rbp, rsp

push rbx

sub rsp, 40

mov QWORD PTR [rbp-40], rdi

mov QWORD PTR [rbp-48], rsi

mov rax, QWORD PTR [rbp-48]

add rax, 2

mov QWORD PTR [rbp-24], rax

cmp QWORD PTR [rbp-40], 0

jne .L2

mov QWORD PTR [rbp-24], 8

jmp .L3

.L2:

mov rax, QWORD PTR [rbp-40]

lea rdx, [0+rax*4]

mov rax, QWORD PTR [rbp-24]

lea rbx, [rdx+rax]

mov rax, QWORD PTR [rbp-48]

lea rdx, [rax+1]

mov rax, QWORD PTR [rbp-40]

sub rax, 1

mov rsi, rdx

mov rdi, rax

call f(long long, long long)

add rax, rbx

mov QWORD PTR [rbp-24], rax

.L3:

mov rdx, QWORD PTR [rbp-24]

mov rax, QWORD PTR [rbp-48]

add rax, rdx

add rsp, 40

pop rbx

pop rbp

ret

Explanation:

8 0
3 years ago
Hello, I've tried everything and I cannot get this code to be fair. I need help. Can someone provide guidance so I can understan
Liula [17]

A program that takes a date as input and outputs the date's season. The input is a string to represent the month and an int to represent the day is given below:

<h3>The Program</h3>

input_month = input()

input_day = int(input())

months= ('January', 'February','March', 'April' , 'May' , 'June' , 'July' , 'August' , 'September' , "October" , "November" , "December")

if not(input_month in months):

  print("Invalid")

elif input_month == 'March':

   if not(1<=input_day<=31):

       print ("Invalid")

   elif input_day<=19:

       print("Winter")

   else:

      print ("Spring")

elif input_month == 'April' :

   if not(1<=input_day<=30):

       print("Invalid")

   else:

      print("Spring")

elif input_month == 'May':

   if not(1<=input_day<=31):

       print("Invalid")

   else:

       print("Spring")

elif input_month == 'June':

   if not(1<=input_day<=30):

       print("Invalid")

   elif input_day<=20:

       print ("Spring")

   else:

       print("Summer")

elif input_month == 'July' or 'August':

   if not(1<=input_day<=31):

       print("Invalid")

   else:

       print("Summer")

elif input_month == 'September':

   if not(1<=input_day<=30):

       print("Invalid")

  elif input_day<=21:

       print ("Summer")

   else:

       print ("Autumn")

elif input_month == "October":

   if not(1<=input_day<=31):

      print("Invalid")

   else:

       print("Autumn")

elif input_month == "November":

   if not(1<=input_day<=30):

       print("Invalid")

   else:

       print ("Autumn")

elif input_month == "December":

   if not(1<=input_day<=31):

       print("Invalid")

   elif input_day <=20:

       print ("Autumn")

   else:

       print ("Winter")

elif input_month == 'January':

   if not(1<=input_day<=31):

       print("Invalid")

   else:

       print("Winter")

elif input_month == "February":

   if not(1<=input_day<=29):

       print("Invalid")

   else:

       print ("Winter")

Read more about programming here:

brainly.com/question/23275071

#SPJ1

5 0
2 years ago
Question 4
Tcecarenko [31]

Answer: squared ← number * number

Explanation:

4 0
3 years ago
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