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3 years ago

0.2x + 0.8 = 9.6 find x Please and thank you.

Mathematics

2 answers:

Akimi4 [234]3 years ago

8 0

Answer:

x=44

Step-by-step explanation:

Making the equation in terms of x:

0.2x + 0.8 = 9.6

-0.8 -0.8

0.2x=8.8

*5 *5

x=44

Ugo [173]3 years ago

5 0

Answer:

x=44

Step-by-step explanation:

Multiply by 10 from both sides of equation.

0.2x*10+0.8*10=9.6*10

Simplify.

2x+8=96

Subtract by 8 from both sides of equation.

2x+8-8=96-8

Simplify.

96-8=88

2x=88

Divide by 2 from both sides of equation.

2x/2=88/2

Simplify, to find the answer.

88/2=44

x=44 is the correct answer.

I hope this helps you, and have a wonderful day!

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The weight of male american between the ages 18 to 25 is normally distributed, with mean of 162.7 lb and a standard deviation of

MArishka [77]

Answer:

218.7 lb.

Step-by-step explanation:

We have been given that the weight of male american between the ages 18 to 25 is normally distributed, with mean of 162.7 lb and a standard deviation of 28 lb.

One definition of obesity states that a person is obese if the z-score of his or her weight is greater than 2.

We will use z-score formula to solve our given problem.

$z=\frac{x-\mu}{\sigma}$ , where,

$z=\text{ z-score}$ ,

$x=\text{ Random sample-score}$ ,

$\mu=\text{ Mean}$ ,

$\sigma=\text{ Standard deviation}$ .

Upon substituting our given values in z-score formula we will get,

$2=\frac{x-162.7}{28}$

Now let us solve for x.

Upon multiplying both sides of our equation by 28 we will get,

$2*28=\frac{x-162.7}{28}*28$

$56=x-162.7$

Let us add 162.7 to both sides of our equation.

$56+162.7=x-162.7+162.7$

$218.7=x$

Therefore, the obesity threshold weight for a young adult American male is 218.7 pounds.

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