Question

Factor this trinomial completely. 2x^2 + 6x + 4

Answer 1

Step-by-step explanation:

$2 {x}^{2} + 6x + 4 \\ \\ = 2 {x}^{2} + 2x + 4x + 4 \\ \\ = 2x(x + 1) + 4(x + 1) \\ \\ = (2x + 4)(x + 1) \\ \\ = 2(x + 2)(x + 1) \\ \\ = 2(x + 1)(x + 2) \\ are \: the \: required \: factors \: of \: the \: \\ given \: trinomial$

Answer 2

Answer: $(x+1)(2x+4)$

Step-by-step explanation:

Given :

$2x^{2}+6x+4$

in order to factorize , we will find two factors that when multiplied together gives $8x^{2}$ and when added gives $6x$.

The factors are : $2x$ and $4x$

The next thing is to replace $6x$ in the trinomial by this two factors , that is

$2x^{2} +2x+4x+4$

Factorizing , we have

$2x(x+1)+4(x+1)$

which will give

$(x+1)(2x+4)$