HELP PLEASE !!!!!!!!! TRUE OR FALSE ?!

Whoever answers this question first gets brainly 2

Margaret [11]

Answer:

1,120

Step-by-step explanation:

180/12=15

for every 15 frogs there would be one with spots

1,200/15=80

1,200 - 80=1,120

7 0

3 years ago

Given the equation square root of quantity 3x plus 6 end quantity equals 3, solve for x and identify if it is an extraneous solu

MissTica

Step-by-step explanation:

3x+6=3

-6 -6

3x =-3

÷3 ÷3

x= -1

4 0

3 years ago

How do you find x? and how do you round to the nearest tenth?

expeople1 [14]

Hey there!

In order to solve this problem, we can use the Pythagorean Theorem, which is $c^2 = a^2 + b^2$ . Since the Pythagorean Theorem would find only half of the length of x, we'll need to double it in the end.

First, let's plug in what we know to the Pythagorean Theorem: $2.1^2 = 1.4^2 + b^2$

Next, we'll simplify to that $b^2$ is by itself:

$b^2 = 2.45$

Then, we'll find the square root of 2.45, multiply that by 2 and round to the nearest tenth:

$2(\sqrt{2.45} ) = 3.1$

Therefore, x = 3.1 ft.

How to round to the nearest tenth:

In a decimal, the tenth is the first number after the decimal point. To round to the tenth, if the number in the hundredth place is less than 5, you keep the number as it is, but if the number in the hundredth place is more than 5, you increase the number in the tenth place by 1.

Hope this helps!! :)

6 0

3 years ago

Someone please help me

allsm [11]

Answer:

Solutions: $x = \frac{-3}{ 4} + i \sqrt{39}$ , $x = \frac{-3}{4} - i \sqrt{39}$

Step-by-step explanation:

Given the quadratic equation, 2x² + 3x + 6 = 0, where a =2, b = 3, and c = 6:

Use the <u>quadratic equation</u> and substitute the values for a, b, and c to solve for the solutions:

$x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}$

$x = \frac{-3 +/- \sqrt{3^{2} - 4(2)(6)} }{2(2)}$

$x = \frac{-3 +/- \sqrt{9- 48} }{4}$

$x = \frac{-3 +/- \sqrt{-39} }{4}$

$x = \frac{-3 + i \sqrt{39} }{4}$ , $x = \frac{-3 - i \sqrt{39} }{4}$

Therefore, the solutions to the given quadratic equation are:

$x = -\frac{3}{ 4} + i \sqrt{39}$ , $x = -\frac{3}{4} - i \sqrt{39}$

4 0

2 years ago

Line FG contains points F (3,7) and G (-4,-5) line HI contains points (-1,0) and I (4,6) lines FG and HI are. ?

ludmilkaskok [199]

FG : (3,7)(-4,-5)
slope = (-5 - 7) / (-4-3) = -12/-7 = 12/7

y = mx + b
slope(m) = 12/7
(3,7)...x = 3 and y = 7
now we sub, we r looking for b, the y int
7 = 12/7(3) + b
7 = 36/7 + b
7- 36/7 = b
49/7 - 36/7 = b
13/7 = b
so ur equation is : y = 12/7 + 13/7.....slope = 12/7, y int = 13/7

HI : (-1,0)(4,6)
slope = (6 - 0) / (4 - (-1) = 6/5

no need to go any farther.....these lines have different slopes...and their not negative reciprocals....so there will be one solution. Answer is : neither.

7 0

3 years ago

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