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icang [17]
4 years ago
13

Can someone pls help me

Mathematics
1 answer:
liberstina [14]4 years ago
4 0

Answer:

Tenth: 6.2

Hundredth: 6.16

Thousandth: 6.159

Step-by-step explanation:

***In general, round up when the number is greater or equal to 5. If number is less, round down***

Rounding to the tenths place means that there will be a SINGLE digit following the decimal. <u>Therefore, 6.1592 rounded to the tenths place will be 6.2 because '5' is equal to 5.</u>

Rounding to the hundredths place means that there will be TWO digits following the decimal. <u>Therefore, 6.1592 rounded to the hundredths place becomes 6.16 because '9' is greater than 5.</u>

Rounding to the thousandths place means that there will be THREE digits after the decimal.<u> 6.1592 rounded to the thousandths place becomes 6.159 because the digit to the right of the thousanths place is '2', meaning you round down. </u>The digit in the thousandths place will stay the same.

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In two months,mica spent a total of $305.43 on groceries.she spent $213.20 in the first month. How much did she spend in her sec
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Answer:

She spent $92.23 in the second month.

Step-by-step explanation:

Subtract the totals:

305.43 - 213.20

= $92.23.

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3 years ago
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Omar's gas tank is 1/10 full. After he buys 6 gallons of gas, it is 2/5 full. How many gallons can Omar's tank hold?
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3 years ago
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Katarina [22]

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4 0
3 years ago
The center of a hyperbola is located at the origin. One focus is located at (−50, 0) and its associated directrix is represented
leva [86]

The equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

The center of a hyperbola is located at the origin that means at (0, 0) and one of the focus is at (-50, 0)

As both center and the focus are lying on the x-axis, so the hyperbola is a horizontal hyperbola and the standard equation of horizontal hyperbola when center is at origin: \frac{x^{2}}{a^{2}}  - \frac{y^{2}}{b^{2}}    = 1

The distance from center to focus is 'c' and here focus is at (-50,0)

So, c= 50

Now if the distance from center to the directrix line is 'd', then

d= \frac{a^{2}}{c}

Here the directrix line is given as : x= 2304/50

Thus, \frac{a^{2}}{c}  = \frac{2304}{50}

⇒ \frac{a^{2}}{50}  = \frac{2304}{50}

⇒ a² = 2304

⇒ a = √2304 = 48

For hyperbola, b² = c² - a²

⇒ b² = 50² - 48² (By plugging c=50 and a = 48)

⇒ b² = 2500 - 2304

⇒ b² = 196

⇒ b = √196 = 14

So, the equation of the hyperbola is : \frac{x^{2}}{48^2}  - \frac{y^{2}}{14^2}  = 1

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3 years ago
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