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Tpy6a [65]
3 years ago
7

Evaluate 5+5*5+5/5-5+5*5

Mathematics
2 answers:
rewona [7]3 years ago
4 0

Answer:

51

Step-by-step explanation:

5*5=25

5/5=1

5+25+1-5+25

30+1-5+25

31-5+25

26+25

51

Helga [31]3 years ago
3 0

Answer:

51

Step-by-step explanation:

5*5=25

5/5=1

5+25+1-5+25

30+1-5+25

31-5+25

26+25

51

You might be interested in
A study of long-distance phone calls made from General Electric Corporate Headquarters in Fairfield, Connecticut, revealed the l
Katena32 [7]

Answer:

(a) The fraction of the calls last between 4.50 and 5.30 minutes is 0.3729.

(b) The fraction of the calls last more than 5.30 minutes is 0.1271.

(c) The fraction of the calls last between 5.30 and 6.00 minutes is 0.1109.

(d) The fraction of the calls last between 4.00 and 6.00 minutes is 0.745.

(e) The time is 5.65 minutes.

Step-by-step explanation:

We are given that the mean length of time per call was 4.5 minutes and the standard deviation was 0.70 minutes.

Let X = <u><em>the length of the calls, in minutes.</em></u>

So, X ~ Normal(\mu=4.5,\sigma^{2} =0.70^{2})

The z-score probability distribution for the normal distribution is given by;

                           Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean time = 4.5 minutes

           \sigma = standard deviation = 0.7 minutes

(a) The fraction of the calls last between 4.50 and 5.30 minutes is given by = P(4.50 min < X < 5.30 min) = P(X < 5.30 min) - P(X \leq 4.50 min)

    P(X < 5.30 min) = P( \frac{X-\mu}{\sigma} < \frac{5.30-4.5}{0.7} ) = P(Z < 1.14) = 0.8729

    P(X \leq 4.50 min) = P( \frac{X-\mu}{\sigma} \leq \frac{4.5-4.5}{0.7} ) = P(Z \leq 0) = 0.50

The above probability is calculated by looking at the value of x = 1.14 and x = 0 in the z table which has an area of 0.8729 and 0.50 respectively.

Therefore, P(4.50 min < X < 5.30 min) = 0.8729 - 0.50 = <u>0.3729</u>.

(b) The fraction of the calls last more than 5.30 minutes is given by = P(X > 5.30 minutes)

    P(X > 5.30 min) = P( \frac{X-\mu}{\sigma} > \frac{5.30-4.5}{0.7} ) = P(Z > 1.14) = 1 - P(Z \leq 1.14)

                                                              = 1 - 0.8729 = <u>0.1271</u>

The above probability is calculated by looking at the value of x = 1.14 in the z table which has an area of 0.8729.

(c) The fraction of the calls last between 5.30 and 6.00 minutes is given by = P(5.30 min < X < 6.00 min) = P(X < 6.00 min) - P(X \leq 5.30 min)

    P(X < 6.00 min) = P( \frac{X-\mu}{\sigma} < \frac{6-4.5}{0.7} ) = P(Z < 2.14) = 0.9838

    P(X \leq 5.30 min) = P( \frac{X-\mu}{\sigma} \leq \frac{5.30-4.5}{0.7} ) = P(Z \leq 1.14) = 0.8729

The above probability is calculated by looking at the value of x = 2.14 and x = 1.14 in the z table which has an area of 0.9838 and 0.8729 respectively.

Therefore, P(4.50 min < X < 5.30 min) = 0.9838 - 0.8729 = <u>0.1109</u>.

(d) The fraction of the calls last between 4.00 and 6.00 minutes is given by = P(4.00 min < X < 6.00 min) = P(X < 6.00 min) - P(X \leq 4.00 min)

    P(X < 6.00 min) = P( \frac{X-\mu}{\sigma} < \frac{6-4.5}{0.7} ) = P(Z < 2.14) = 0.9838

    P(X \leq 4.00 min) = P( \frac{X-\mu}{\sigma} \leq \frac{4.0-4.5}{0.7} ) = P(Z \leq -0.71) = 1 - P(Z < 0.71)

                                                              = 1 - 0.7612 = 0.2388

The above probability is calculated by looking at the value of x = 2.14 and x = 0.71 in the z table which has an area of 0.9838 and 0.7612 respectively.

Therefore, P(4.50 min < X < 5.30 min) = 0.9838 - 0.2388 = <u>0.745</u>.

(e) We have to find the time that represents the length of the longest (in duration) 5 percent of the calls, that means;

            P(X > x) = 0.05            {where x is the required time}

            P( \frac{X-\mu}{\sigma} > \frac{x-4.5}{0.7} ) = 0.05

            P(Z > \frac{x-4.5}{0.7} ) = 0.05

Now, in the z table the critical value of x which represents the top 5% of the area is given as 1.645, that is;

                      \frac{x-4.5}{0.7}=1.645

                      {x-4.5}{}=1.645 \times 0.7

                       x = 4.5 + 1.15 = 5.65 minutes.

SO, the time is 5.65 minutes.

7 0
3 years ago
IS MY ANSWER CORRECT??? If not what’s the correct answer
Kazeer [188]

Answer:

yes

Step-by-step explanation:

your answer is correct

4 0
2 years ago
Read 2 more answers
College precalc! Please help! I've been struggling.
kiruha [24]

Answer:

B) f(x) = x if x ≤ -2

            2 if x > -2

Step-by-step explanation:

B) f(x) = x if x ≤ -2 (The x and y coordinate have the same value)

            2 if x > -2

8 0
3 years ago
Solve x(x-1) (X-5) &lt;=O​
lara [203]

Answer:

x <= 0 or  1 = < x <= 5.

Step-by-step explanation:

First we find the critical points:

x(x - 1)(x - 5) = 0

gives x = 0, x = 1 and x = 5.

Construct a Table of values:

               <u>  x < 0 </u>  <u>x = 0 </u> 0<u>< x < 1</u>  <u>1 =< x <= 5</u>     <u>x = 5</u>

x                  <0        0          >0             <0           0

x - 1             <0       -1           >0              <0           0

x - 5            < 0       0          > 0             <0           0

x(x-1)(x-5)    < 0      0          >0              <0          0 

So the answers are x =< 0 or  1 =< x <= 5.

8 0
3 years ago
Naomi can spend up to $18.00 for a trip to the bowling alley. The cost per game is $3.25, and shoe rental for the day is $1.50.
Alja [10]

Answer:

The answer for this question is D

Step-by-step explanation:

because x represents the number of games which is unknown plus 1.50 for the shoe rental

3 0
3 years ago
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