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3 years ago

8

Find the factors of 42 showing explain your work and this is the factor pairs in a table

2 answers:

Ilya [14]3 years ago

6 0

Fundamental Theorem of Arithmetic states that every positive integer can be factor into a product of unique primes.
42=2*3*7
therefore all factors of 42 are all the combinations of the product
2, 3, 7, 6, 14, 21
and 1,42 in case you wanted to include them as well.

irga5000 [103]3 years ago

5 0

1,2,3,6,7,14,21,and42

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Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

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3 years ago

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Answer:

The work is in the explanation.

Step-by-step explanation:

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$\sin(a-b)=\sin(a)\cos(b)-\cos(a)\sin(a)$ .

The cosine addition identity is:

$\cos(a+b)=\cos(a)\cos(b)-\sin(a)\sin(b)$ .

The cosine difference identity is:

$\cos(a-b)=\cos(a)\cos(b)+\sin(a)\sin(b)$ .

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Let's start there then.

There is a plus sign in between them so let's add those together:

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$=[\sin(a)\cos(b)+\cos(a)\sin(b)]+[\sin(a)\cos(b)-\cos(a)\sin(b)]$

There are two pairs of like terms. I will gather them together so you can see it more clearly:

$=[\sin(a)\cos(b)+\sin(a)\cos(b)]+[\cos(a)\sin(b)-\cos(a)\sin(b)]$

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Divide both sides by 2:

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By the symmetric property we can write:

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3 years ago