Here's link
to the answer:
bit.
ly/3gVQKw3
Answer:
14
Step-by-step explanation:
Given the indicinal expression 64^5/6 + 27^2/3 - 81^3/4
According to indices;
![a^{m/n} = (\sqrt[n]{a}) ^m](https://tex.z-dn.net/?f=a%5E%7Bm%2Fn%7D%20%3D%20%28%5Csqrt%5Bn%5D%7Ba%7D%29%20%5Em)
Applying this to the question
![64^{5/6} \\= (\sqrt[6]{64}) ^5\\= 2^5= 32](https://tex.z-dn.net/?f=64%5E%7B5%2F6%7D%20%5C%5C%3D%20%28%5Csqrt%5B6%5D%7B64%7D%29%20%5E5%5C%5C%3D%202%5E5%3D%2032)
Similarly
![27^{2/3}\\= (\sqrt[3]{27}) ^2\\= 3^2\\= 9\\](https://tex.z-dn.net/?f=27%5E%7B2%2F3%7D%5C%5C%3D%20%28%5Csqrt%5B3%5D%7B27%7D%29%20%5E2%5C%5C%3D%203%5E2%5C%5C%3D%209%5C%5C)
Also;
![81^{3/4}\\= (\sqrt[4]{81}) ^3\\= 3^3\\= 27](https://tex.z-dn.net/?f=81%5E%7B3%2F4%7D%5C%5C%3D%20%28%5Csqrt%5B4%5D%7B81%7D%29%20%5E3%5C%5C%3D%203%5E3%5C%5C%3D%2027)
Substitute inti the original equation
64^5/6 + 27^2/3 - 81^3/4
= 32 + 9- 27
= 41 - 27
= 14
Hence the required answer is 14
<span>5(x-3)-2(2x+1)
5x - 15 - 4x - 2
(5x - 4x) - 15 - 2
x - 15 - 2
x - 17
The answer is: x - 17.</span>
D (5x9)x because the parentheses are switched but the values are the same
<span>Given
number = p + 6 = 1
Before answering, let us first show the solution on how to get the correct
answer
=> we have p + 6 = 18, where p is a variable and 6 and 18 are integers.
=> P + 6 =118, move 6 to the right side, since we are going to move it, the
value of it will be negative
=> P = 18 – 6
=> p = 12
Thus, the answer is b. P = 12</span><span>
</span>