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3 years ago

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1. Write a number whose square is between 200 and 300.

1 answer:

Nadya [2.5K]3 years ago

8 0

15

Square root of 200 = 14.14
Square root of 300 = 17.32

15^2 = 225

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3 x 10^4 in standard form

Art [367]

Answer: 3x10=30

3x10(with the power of 2)=300

3x10(with the power of 3)=3000

3x10(witht the power of 4)=3000

Step-by-step explanation:

sorry if this dont help

6 0

2 years ago

One patterned blue fabric sells for $15.00 every two yards, and another sells for $37.50 every 5 yards. Do these fabrics have th

Svetradugi [14.3K]

All we need to do is to find out how much is worth one yard in both fabrics, so we divide $15.00 by 2 and $37.50 by 5:

$15.00 ÷ 2 = $7.50 per yard
$37.50 ÷ 5 = $7.50 per yard

As both prices per yard are the same, the answer is: <u>Yes, these fabrics have the same unit cost.</u>

6 0

3 years ago

PLEASE HELP ASAP AND THANKS Find x

baherus [9]

Answer:

The value of x is 2.

Step-by-step explanation:

First, you have to make the left side into 1 fraction by making the denorminator the same :

$\frac{x}{x - 2} + \frac{1}{5}$

$= \frac{5x}{5(x - 2)} + \frac{x - 2}{5(x - 2)}$

$= \frac{5x + x - 2}{5(x - 2)}$

$= \frac{6x - 2}{5(x - 2)}$

Then you have to do cross multiplication :

$\frac{6x - 2}{5(x - 2)} = \frac{2}{x - 2}$

$(6x - 2)(x - 2) = 5(2)(x - 2)$

$6 {x}^{2} - 12x - 2x + 4 = 10x - 20$

$6 {x}^{2} - 14x + 4 = 10x - 20$

$6 {x}^{2} - 14x + 4 - 10x + 20 = 0$

$6 {x}^{2} - 24x + 24 = 0$

$6( {x}^{2} - 4x + 4) = 0$

${x}^{2} - 4x + 4 = 0$

${x}^{2} - 2x - 2x + 4 = 0$

$x(x - 2) - 2(x - 2) = 0$

$(x - 2)(x - 2) = 0$

$x = 2$

5 0

3 years ago

Please help me solve this

Viktor [21]

You can factor the 32 out of the sum:

$\displaystyle \sum_{m=1}^\infty 32 \cdot \left(\dfrac{1}{2}\right)^{m-1} = 32\sum_{m=1}^\infty \left(\dfrac{1}{2}\right)^{m-1}$

We can also change the index as follows

$\displaystyle 32\sum_{m=1}^\infty \left(\dfrac{1}{2}\right)^{m-1} = 32\sum_{m=0}^\infty \left(\dfrac{1}{2}\right)^{m}$

Now, we have a theorem that states that the series

$\displaystyle \sum_{m=1}^\infty a^m$

converges if and only if $|a|$ , and in this case we have

$\displaystyle \sum_{m=1}^\infty a^m = \dfrac{1}{1-a}$

This is your case, because you have

$|a|=\dfrac{1}{2}$

which implies that your series converges, and the value is

$\displaystyle 32\sum_{m=0}^\infty \left(\dfrac{1}{2}\right)^{m} = 32 \cdot \dfrac{1}{1-\frac{1}{2}} = 32\cdot 2 = 64$

3 0

3 years ago

Modular arithmetic<br> Pls a little explaine it

fredd [130]

Step-by-step explanation:

(72)¹⁴³ ≡ x (mod 7)

Since 72 ≡ 2 (mod 7),

72³ ≡ 2³ (mod 7) ≡ 1 (mod 7).

Therefore (72)¹⁴³ = (72³)⁴⁷ * (72²)

≡ 1⁴⁷ * 4 (mod 7) ≡ 4 (mod 7).

The answer is A.

6 0

3 years ago