Answer:
Its 4:)
Step-by-step explanation:
Answer:
900 front row seats
Step-by-step explanation:
Tickets for front row seat = 220 dollars (y)
Cost of remaining seats ticket = 50 dollars (z)
Number of front row seats = x
Number of remaining seats = 2050 (w)
Total amount earned when stadium is full = 300,500 dollars (T)
so if we formulate this using our variables y,z,x,w and T problem it becomes:
y*x + z*w = T, which says the
Tickets for front row seat times Number of front row seats plus Cost of remaining seats ticket times Number of remaining seats gives us Total amount earned by the stadium.
220*x + 2050*50 = 300500
220*x = 300500-102500
220*x = 198000
divide both side by 220
x = 900
Options
(A) (9,0) (B) (-2,20) (C) (-5,2) (D) (0,-9)
Answer:
(B) (-2,20)
Step-by-step explanation:
Given the objective function, C=3x-4y
The vertex at which C is minimized will be the point (x,y) at which the expression gives the lowest value.
<u>Option A </u>
At (9,0), x=9, y=0
C=3(9)-4(0)=27-0
C=27
<u>Option B </u>
At (-2,20), x=-2, y=20
C=3(-2)-4(20)=-6-80
C=-86
<u>Option C</u>
At (-5,2), x=-5, y=2
C=3(-5)-4(2)=-15-8
C=-23
<u>Option D </u>
At (0,-9), x=0, y=-9
C=3(0)-4(-9)=0+36
C=36
The lowest value of C is -86. This occurs at the vertex (-2,20).
Therefore, the objective function C=3x-4y is minimized at (-2,20).
Answer:
the third slot should be 5x+4-9+x
then the last one should be 6x-5
