Do you know how to do integer exponents

[30 POINTS] Please help!!!

Len [333]

Answer:

Part 1) $y=1.5x+5$

Part 2) $y=-(2/3)x-(11/3)$

Part 3) $y=0.25x+2.75$

Part 4) $y=-2x+5$

Part 5) $y=0.5x-1$

Part 6) The graph in the attached figure

Step-by-step explanation:

Part 1) we have

$m=3/2=1.5$

$point(-2,2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-2=1.5(x+2)$

$y=1.5x+3+2$

$y=1.5x+5$

Part 2) we know that

If two lines are perpendicular

then

the product of their slopes is equal to minus one

so

$m1*m2=-1$

the slope of the line 1 is equal to

$m1=1.5$

Find the slope m2

$1.5*m2=-1$

$m2=-2/3$

Find the equation of the line 2

we have

$m2=-2/3$

$point(-7,1)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-1=(-2/3)(x+7)$

$y=-(2/3)x-(14/3)+1$

$y=-(2/3)x-(11/3)$

Part 3) we have

$m=1/4=0.25$

$point(1,3)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y-3=0.25(x-1)$

$y=0.25x-0.25+3$

$y=0.25x+2.75$

Part 4) we have

$m=-2$

$b=5$ -----> y-intercept

we know that

The equation of the line into slope intercept form is equal to

$y=mx+b$

substitute the values

$y=-2x+5$

Part 5) we have that

The slope of the line 4 is equal to $-2$

so

the slope of the line perpendicular to the line 4 is equal to

$-2*m=-1\\m=(1/2)=0.5$

therefore

in this problem we have

$m=0.5$

$point(-2,-2)$

The equation of the line into point slope form is equal to

$y-y1=m(x-x1)$

substitute

$y+2=0.5(x+2)$

$y=0.5x+1-2$

$y=0.5x-1$

Part 6)

using a graphing tool

see the attached figure

3 0

3 years ago

Amelia launched her science fair rocket, and then backed away. The path of the rocket is given by the equation below, where y is

Mamont248 [21]

Answer:

1)The rocket hit the ground at $x = \frac{5}{4}$

2)The maximum height of the rocket = 12.468 feet

Step-by-step explanation:

Step(i):-

Given equation

y = -2 x² + 5 x + 7 ...(i)

Differentiating equation (i) with respective to 'x' , we get

$\frac{dy}{dx} = -2( 2x) +5(1) = -4x +5$

Equating zero

$\frac{dy}{dx} = 0$

⇒ -4 x +5 =0

⇒ -4 x = -5

⇒ $x = \frac{5}{4}$

The rocket hit the ground at $x = \frac{5}{4}$

Step(ii):-

$\frac{dy}{dx} = -4x +5$ ...(ii)

Again differentiating equation (ii) with respective to 'x' , we get

$\frac{d^{2} y}{dx^{2} } = - 4(1)$

The maximum height at x = $\frac{-5}{4}$

y = -2 x² + 5 x + 7

$y = -2 (\frac{5}{4})^{2} + 5 (\frac{5}{4} ) + 7$

$y = \frac{-2(25)+ 25 (16)+7(64)}{64}$

$y = \frac{798}{64} = 12.468 feet$

The maximum height of the rocket = 12.468 feet

4 0

3 years ago

A bouquet of flowers contains a total of 24 red and white roses. The number of red roses is 4 less than three times the number o

geniusboy [140]

Answer:

White roses - 7

Red roses - 17

Step-by-step explanation:

Set up proportional equations

White roses = x

Red roses = 3x - 4

Set equal to 24

x + 3x - 4 = 24

4x - 4 = 24

4x = 28

x = 7

x is white roses, so there are 7

Plug x value into red rose equation

3(7)-4

21-4 = 17 red roses

Check

17+7 = 24

5 0

3 years ago

Please help I only have an hour.

Goshia [24]

Answer:

Slope (m) = $\frac{y}{x} = \frac{2}{3} = 0.66666666666667$

Step-by-step explanation:

$0 = arctan (\frac{y}{x}) = 33.69006752598°$

X = 4 – 1 = 3

Y = 4 – 2 = 2

$Distance (d) = \sqrt{x^2+y^2}= \sqrt{13} =3.605551275464$

Equation of the line:

y = 0.66666666666667x + 1.3333333333333

or

$y=\frac{2}{3}x+\frac{4}{3}$

When x=0, y = 1.3333333333333

When y=0, x = -2

4 0

2 years ago

What are transformations?

Nuetrik [128]

Answer:

a transformation happen when the shape changes. There are four transformations

translation

rotation

reflection

dilation

translation, rotation and reflection do not change the shape or the size of the shape and are known as rigid motions

3 0

3 years ago