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3 years ago

16x^2-16x=5 solve the equation by completing the square

Mathematics

1 answer:

Ivanshal [37]3 years ago

7 0

This is your answer: x= -1/4 or x=5/4. Plze mark me brainiest:)

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Original price: ? Percent of discount: 25% Sale price: $45

My name is Ann [436]

Answer:

Original price is 11.25

Step-by-step explanation:

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3 years ago

Read 2 more answers

What is the lcm of 150 and 180

xxTIMURxx [149]

Answer:

900

Step-by-step explanation:

multiply 2x2x3x3x5x5

4x9x25 which is 900

8 0

3 years ago

The two triangles below are similar. What value of Q and B would make this true

Alenkinab [10]

Answer:

∠B = ∠Q = 26°

Step-by-step explanation:

The angles B and Q should be same, therefore:

Q = 4x + 2 and B = 15x - 64

The equation below as per above, solving for x:

4x + 2 = 15x - 64
15x - 4x = 64 +2
11x = 66
x = 6

Then the angle measures:

4*6 + 2 = 26°

6 0

3 years ago

A dress is on sale for $192. What was the original price of the dress if the discount was 1/5 of the original price?

Alexeev081 [22]

Answer:

$240

Step-by-step explanation:

Let x = the original price:

x - 0.2x = 192

0.8x = 192

x = 240

6 0

2 years ago

第 5 个问题 a multiple choice exam has 10 questions. each question has 3 possible answers, of which one is correct. a student knows

tatuchka [14]

The chances that the student was merely guessing is 1/3.

Bayes Theorem determines the conditional probability of an event A given that event B has already occurred.

denoted by

$P(A/B)=\frac{P(A)*P(B/A)}{P(B)}$

let A be the event that the student knows the answer .

B be the event that the student does not knows the answer .

and

E be the event he gets answer correct .

According to the given question

$P(A)=\frac{4}{10} \\\\ P(B)=1-\frac{4}{10} =\frac{6}{10}$

Probability that the answer is correct ,given that he knows the answer is

$P(E/A)=1$

Probability that the answer is correct ,given that he guesses it is

$P(E/B)=\frac{1}{3}$ [as the MCQ has 3 options and only one is correct]

We need to find the probability that he guesses the answer given that it is correct.

Required probability $P(B/E)=\frac{P(B)*P(E/B)}{P(A)*P(E/A)+P(B)*P(E/B)}$

Substituting the values we get

$P(B/E)=\frac{\frac{6}{10} *\frac{1}{3} }{\frac{4}{10} *1+\frac{6}{10} *\frac{1}{3} }$

$=\frac{6}{30}*\frac{30}{18} \\ \\ =\frac{6}{18} \\ \\ =\frac{1}{3}$

Therefore , the chances that the student was merely guessing is 1/3.

Learn more about Probability here brainly.com/question/13140147

#SPJ4

8 0

1 year ago