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Mila [183]
3 years ago
6

16x^2-16x=5 solve the equation by completing the square

Mathematics
1 answer:
Ivanshal [37]3 years ago
7 0

This is your answer: x= -1/4 or x=5/4. Plze mark me brainiest:)

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Original price: ?<br><br> Percent of discount: 25%<br><br> Sale price: $45
My name is Ann [436]

Answer:

Original price is 11.25

Step-by-step explanation:

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What is the lcm of 150 and 180
xxTIMURxx [149]

Answer:

900

Step-by-step explanation:

multiply 2x2x3x3x5x5

4x9x25 which is 900

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The two triangles below are similar. What value of Q and B would make this true
Alenkinab [10]

Answer:

  • ∠B = ∠Q = 26°

Step-by-step explanation:

<u>The angles B and Q should be same, therefore:</u>

  • Q = 4x + 2 and B = 15x - 64

<u>The equation below as per above, solving for x:</u>

  • 4x + 2 = 15x - 64
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  • x = 6

<u>Then the angle measures:</u>

  • 4*6 + 2 = 26°

6 0
3 years ago
A dress is on sale for $192. What was the original price of the dress if the discount was 1/5 of the original price?
Alexeev081 [22]

Answer:

$240

Step-by-step explanation:

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6 0
2 years ago
第 5 个问题 a multiple choice exam has 10 questions. each question has 3 possible answers, of which one is correct. a student knows
tatuchka [14]

The chances that the student was merely guessing is 1/3.

Bayes Theorem determines the conditional probability of an event A given that event B has already occurred.

denoted by

P(A/B)=\frac{P(A)*P(B/A)}{P(B)}

let A be the  event that the student knows the answer .

B be  the  event that the student does not knows the answer .

and

E be the event he gets answer correct .

According to the given question

P(A)=\frac{4}{10} \\\\ P(B)=1-\frac{4}{10} =\frac{6}{10}

Probability that the answer is correct ,given that he knows the answer is

P(E/A)=1

Probability that the answer is correct ,given that he guesses it is

P(E/B)=\frac{1}{3}   [as the MCQ has 3 options and only one is correct]

We need to find the probability that he guesses the answer given that it is correct.

Required probability P(B/E)=\frac{P(B)*P(E/B)}{P(A)*P(E/A)+P(B)*P(E/B)}

Substituting the values we get

P(B/E)=\frac{\frac{6}{10} *\frac{1}{3} }{\frac{4}{10} *1+\frac{6}{10} *\frac{1}{3} }

=\frac{6}{30}*\frac{30}{18}  \\ \\ =\frac{6}{18} \\ \\ =\frac{1}{3}

Therefore ,  the chances that the student was merely guessing is 1/3.

Learn more about Probability here brainly.com/question/13140147

#SPJ4

8 0
1 year ago
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