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4 years ago

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X-4y=-18 Graphing Linear Equations in 2 Variables

1 answer:

lara31 [8.8K]4 years ago

6 0

Well it think it 16 your welcome

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Please show me how to COMPLETELY factor this expression.

ss7ja [257]

The answer is
(z+14)(z-3)

6 0

3 years ago

Consider two functions f and g on [1, 8] such that integral^8_1 f(x) dx = 9, integral^8_1 g(x) dx = 5, integral^8_5 f(x) dx = 4,

Gelneren [198K]

I'll abbreviate the definite integral with the notation,

$I(f(x),a,b)=\int_a^bf(x)\,\mathrm dx$

We're given

$I(f,1,8)=9$
$I(g,1,8)=5$
$I(f,5,8)=4$
$I(g,1,5)=3$

Recall that the definite integral is additive on the interval $[a,b]$ , meaning for some $c\in[a,b]$ we have

$I(f,a,b)=I(f,a,c)+I(f,c,b)$

The definite integral is also linear in the sense that

$I(kf+\ell g,a,b)=kIf(a,b)+\ell I(g,a,b)$

for some constant scalars $k,\ell$ .

Also, if $a\ge b$ , then

$I(f,a,b)=-I(f,b,a)$

a. $I(2f,1,5)=2I(f,1,5)=2(I(f,1,8)-I(f,5,8))=2(9-4)=\boxed{10}$

b. $I(f-g,1,8)=I(f,1,8)-I(g,1,8)=9-5=\boxed{4}$

c. $I(f-g,1,5)=I(f,1,5)-I(g,1,5)=\dfrac{I(2f,1,5)}2-I(g,1,5)=10-3=\boxed{7}$

d. $I(g-f,5,8)=I(g,5,8)-I(f,5,8)=(I(g,1,8)-I(g,1,5))-I(f,5,8)=(5-3)-4=\boxed{-2}$

e. $I(7g,5,8)=7I(g,5,8)=7(5-3)=\boxed{14}$

f. $I(3f,5,1)=3I(f,5,1)=-3I(f,1,5)=-\dfrac32I(2f,1,5)=-\dfrac32(10)=\boxed{-15}$

4 0

3 years ago

You’re having dinner at a restaurant that serves 5 kinds of pasta (spaghetti, bow ties, fettuccine, ravioli, and macaroni) in 4

Rama09 [41]

There are five different pasta choices. The probability for you to pick one of them is: 1/5
There are four different flavors. The probability for you to pick one of them is: 1/4

The probability for you to pick both bow ties and cheese sauce is the same as picking ravioli and olive oil, or spaghetti and meat sauce.
The probability is: 1/5 x 1/4 = 0.05

Read more on Brainly.com - brainly.com/question/9230316#readmore

8 0

3 years ago

Read 2 more answers

Evaluate x Square-4x for x=-7

Ivahew [28]

ANSWER:

(-7)^2-4*(-7)
=49+28
=77

Hope it helps u! :)

7 0

3 years ago

Read 2 more answers

A box is supposed to have 150 folders in it. Clare counts only 147 folders in

VikaD [51]

Answer:

it's a 0.02% error.

147/150= 0.98% of the folders are there, making the error 0.02%

Step-by-step explanation:

5 0

3 years ago