What is the general rule for the nth -2,8,18,28,38

My number is a multiple of 15 it is also a multiple of 10 it is greater rthan 100 and less than 200

alexandr402 [8]

150. 15*10 = 150, and its in-between 100 and 200.

4 0

3 years ago

In triangle ABC, the measure of angle B is 50 degrees. Give possible values for the measures of angles A and C if ABC is a right

Rasek [7]

9514 1404 393

Answer:

A = 90°, C = 40°
A = 40°, C = 90°

Step-by-step explanation:

In a right triangle one angle is 90° and the other angle is the complement of the acute angle given.

Angles A and C are not specified, but we know the other two angles are 40° and 90°. The values can be assigned two ways:

A = 90°, C = 40°

A = 40°, C = 90°

5 0

2 years ago

X + 8 + 2x <= 2x + 13

sergejj [24]

Answer:

X = 15

Step-by-step explanation:

We move all terms to the left:

x+8+2x-(2x+13)=0

We add all the numbers together, and all the variables:

3x-(2x+13)+8=0

We get rid of parentheses:

3x-2x-13+8=0

We add all the numbers together, and all the variables:

x-5=0

We move all terms containing x to the left, all other terms to the right:

x=5

5 0

2 years ago

f(x) = 3x2 - 2x g(x) = x + 4 When finding f(x) · g(x), what could the first step look like? A) 3x2 + 12x2 - 2x2 - 8x B) 3x2 + 7x

Anna71 [15]

(3x^2 - 2x)(x + 4)

First step would be: distributive property.

3x^3 + 12x^2 - 2x^2 - 8x

Combine like terms.

3x^3 + 10x^2 - 8x is the simplified form of the functions multiplied.

Your answer is D.

3 0

3 years ago

Find the quotient of (11 ^ 18)/(11 ^ 3)

astraxan [27]

Answer:

The first choice, $11^{15}$ .

Step-by-step explanation:

The numerator, $11^{18}$ , is equivalent to eighteen " $11$ " multiplied together:

$11^{18} = \underbrace{11 \times 11 \times 11 \times 11 \times \cdots \times 11 \times 11}_{\text{$18$ in total}}$ .

On the other hand, the denominator, $11^{3}$ , is equivalent to three " $11$ " multiplied with one another:

$11^{3} = 11 \times 11 \times 11$ .

Dividing $11^{18}$ by $11^{3}$ would eliminate three " $11$ " from the numerator:

$\begin{aligned}& \frac{11^{18}}{11^{3}} \\ =\; & \frac{(11 \times 11 \times 11) \times \overbrace{11 \times \cdots \times 11}^{\text{$(18 - 3)$ in total}}}{(11 \times 11 \times 11)} \\ =\; & \overbrace{11 \times \cdots \times 11}^{\text{$15$ in total}} \\ =\; & 11^{15}\end{aligned}$ .

In general, dividing an expression by $y^{b}$ ( $y \ne 0$ ) is equivalent to multiplying that expression by $y^{-b}$ .

For example, in this question, dividing $11^{18}$ by $11^{3}$ would be equivalent to multiplying $11^{18}\!$ by $11^{-3}$ . In other words:

$\begin{aligned}& \frac{11^{18}}{11^{3}} \\ =\; & 11^{18} \times 11^{-3} \\ =\; & 11^{18 - 3} \\ =\; & 11^{15}\end{aligned}$ .

6 0

2 years ago