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Kipish [7]
3 years ago
13

A card is drawn at random from a standard pack of playing cards then a fair coin is flipped what is the probability of selecting

an ace and coin landing on heads
Mathematics
1 answer:
yarga [219]3 years ago
6 0

Answer:

what is the options

Step-by-step explanation:

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Can you please solve 2x+29+3x - 4
love history [14]

Answer:

5x + 25

Step-by-step explanation:

2x+29+3x+4

Step 1: Arrange it:- 2x+3x+29-4

Step 2:- Add and Subtract the terms:- 5x + 25

HOPE IT HELPS!

8 0
2 years ago
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Pls helppppp!!
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1) -5-4i
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3 years ago
Sinθ+cotθ×cosθ=cscθ​
Assoli18 [71]

Answer:

Step-by-step explanation:

\sin \theta+\cot \theta\cos \theta=\sin \theta+\displaystyle \frac{\cos \theta}{\sin \theta}\cos \theta=\frac{\sin^2 \theta+\cos ^2 \theta}{\sin \theta}=\\\frac{1}{\sin \theta}=\csc \theta

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3 years ago
X and y are in direct proportion, when x is 8, y is 12. Which of the following is not a
Nat2105 [25]

Answer:

d.

Step-by-step explanation:

if x varies directly as y,

x = ky

8 = 12k

12k = 8

k = 8/ 12

k = 2/3,

x = 2/3 y

now substitute the value of any of the numbers of each pair, and check if it works:

for e.g, find x when y = 15

x = 2/3y

x = 2/3 × 15

x = 10

since you obtain x = 10 when y = 15, the pair is a possible corresponding value of x and y. now do the same for the rest .

ii) x = 2/3y

x = 2/3 × 3, when y = 3

x = 2

hence, this is also a possible pair of x and y values.

iii) x = 2/3y

x = 2/3 × 9 when y = 9

x = 6

again, a possible pair of x and y values.

iv) x = 2/3y

x = 2/3 × 20 when y = 20

x = 40/3

here, when y = 20, x is not 15. it is 40/3.

thus, it can be determined that this is not a possible pair of x and y values.

please try to understand and have a great day!

8 0
2 years ago
A boat takes 1.6 hours longer to move up a
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I don’t even know sorry
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3 years ago
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