Answer:
Question 1:
Here total number of students GPA is given = 50
Number of people who have GPA more than 3.69 = 5
Therefore,
Pr(That a student has GPA more than 3.69) = 5/50 = 0.1
Here X ~ NORMAL (3.12, 0.4)
so Pr(X > 3.69) = Pr(X > 3.69 ; 3.12 ; 0.4)
Z = (3.69 - 3.12)/ 0.4 = 1.425
Pr(X > 3.69) = Pr(X > 3.69 ; 3.12 ; 0.4) = 1 - Pr(Z < 1.425) = 1 - 0.9229 = 0.0771
Question 2
Here GPA would be above 95.54th percentile
so as per Z table relative to that percentile is = 1.70
so Z = (X - 3.12)/ 0.4 = 1.70
X = 3.12 + 0.4 * 1.70 = 3.80
so any person with GPA above or equal to 3.80 is eligible for that.
Oma made a mistake in step B, because she should have divided both sides by b instead of just moving it to the other side. The real next step would look like:
(2A)/b=h
He should take $20 an hour because he will get $50 more than the 15% on all his sales
It is an irrational number which means that it cannot be written as a ratio or fraction. It also does not end nor repeat.
√3≈ 1.73205080757
(approximately equal to) ≈
The answer is 308 by multiple
