The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:<span>

<span> $|PQ|= \sqrt{ (a-c)^{2} + (b-d)^{2}}$ </span></span>

Using this formula we calculate the distances |PA|, |PB|, |PC|, |PD| and |PE| and compare to 5.

$|PA|= \sqrt{ (-2-2)^{2} + (-2-1)^{2}}= \sqrt{16+9}= \sqrt{25}=5$

$|PB|= \sqrt{ (-2-4)^{2} + (-2+1)^{2}}= \sqrt{36+1}= \sqrt{37} \approx 6$

$|PC|= \sqrt{ (-2-2)^{2} + (-2+3)^{2}}= \sqrt{16+1}= \sqrt{17}\approx4$

$|PD|= \sqrt{ (-2+6)^{2} + (-2+6)^{2}}= \sqrt{16+16}= \sqrt{32}\ \textgreater \ \sqrt{25}=5$

$|PE|= \sqrt{ (-2+5)^{2} + (-2-1)^{2}}= \sqrt{9+9}= \sqrt{16}=4$

Answer: B and D

3 0

3 years ago

Eileen collected 78 empty cans to recycle, and Carl collected 62 cans. They packed an equal number of cans into each of seven bo

AVprozaik [17]

Answer:

20 cans

Step-by-step explanation:

Eileen collected 78 empty cans to recycle

Carl collected 62 empty cans to recycle

They pack equal number of cans in 7 boxes

Therefore the number of cans in each boxes can be calculated as follows.

= 62 + 78/7

= 140/7

= 20

Hence there were 20 cans in each boxes

8 0

2 years ago