Total surface area of the present=
=2*(5 in * 4.5 in)+2*(5 in * 3.5 in) + 2*(4.5 in * 3.5 in)=
=45 in² + 35 in² + 31.5 in²=111.5 in²
answer:the total surface area of the present is 111.5 in²
b). empty set, {–3}, {6}, {–3, 6}
f(x) = tan2(x) + (√3 - 1)[tan(x)] - √3 = 0
tan2(x) + √3[tan(x)] - tan(x) - √3 = 0
Factor into
[-1 + tan(x)]*[√3 + tan(x)] = 0
which means
[-1 + tan(x)] = 0 and/or [√3 + tan(x)] = 0
Then
tan(x) = 1
tan-1(1) = pi/4 radians
For the other equation
[√3 + tan(x)] = 0
tan(x) = -√3
tan-1(-√3) = -pi/3
so that
x = pi/4 or -pi/3 in the interval [0, 2pi]
Answer:
twenty fifth
Step-by-step explanation:
