Answer:
0.7061 = 70.61% probability she will have her first crash within the first 30 races she runs this season
Step-by-step explanation:
For each race, there are only two possible outcomes. Either the person has a crash, or the person does not. The probability of having a crash during a race is independent of whether there was a crash in any other race. This means that the binomial probability distribution is used to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
A certain performer has an independent .04 probability of a crash in each race.
This means that 
a) What is the probability she will have her first crash within the first 30 races she runs this season
This is:

When 
We have that:



0.7061 = 70.61% probability she will have her first crash within the first 30 races she runs this season
Answer:
It is not correct, x = -5
Step-by-step explanation:
Answer: <
im sorry if this is wrong im not entirely sure :(
$33,075 = 0.05S + S
$33,075 = 1.05S
$33,075/1.05 = 1.05S/1.05
S= $31,500
Check
$31,500 * 5% = $1575 + $31,500 =$33,075
Answer:
P(x< 18) = 0.986
Step-by-step explanation:
Step 1: find the z-score using the formula, z = (x - µ)/σ
Where,
x = randomly chosen values = 18
µ = mean = 7
σ = standard deviation = 5
Proportion of the population that is less than 18 = P(x < 18)
Plug in the values into z = (x - µ)/σ, to get z-score.
z = (18 - 7)/5
z = 11/5 = 2.2
Step 2: Find P(x< 18) = P (z<2.2) using z-table.
The probability that corresponds with z-score calculated is 0.986.
Therefore,
P(x< 18) = 0.986