(k+2) (k-1-3) :

Manda converted the following repeating decimal a fraction. Her work is shown below.

Butoxors [25]

In analyzing Manda’s work, she made a mistake instep 3, she did not subtract one x from the left side.

<h3>What is the fraction about?</h3>

Fractions are known to be the parts of a complete or whole numbers of objects. It is known to have a numerator and a denominator and when solving for it, the rule of BODMAS must be obeyed.

In step 3 we see that (image attached) she did not subtract one x from the left side. The right thing to do is to use x to cancel out on the both side and that will make the answer to be correct but she did not.

So her error is seen in step 3 and as such, option C is correct.

See full question in the image attached.

Options are

Analyze Manda’s work. Is she correct? If not, what was her mistake?

A. Yes, she is correct.

B. In step 2, she needed to multiply both sides by 10.

C. In step 3, she did not subtract one x from the left side.

D. In step 4, she did not simplify her fraction.

Learn more about fraction from

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6 0

3 years ago

If 6y-8=28, what is the value of y

quester [9]

The answer would be y = 6

8 0

4 years ago

Read 2 more answers

In recent years more people have been working past the age of 65. In 2005, 27% of people aged 65–69 worked. A recent report from

Vinil7 [7]

Answer:

a) point estimate is 30%

b) null and alternative hypothesis would be

$H_{0}$ : p=27%

$H_{a}$ : p>27%

c) We reject the null hypothesis, percentage working people aged 65-69 had increased

Step-by-step explanation:

<em>a. </em>

Point estimate would be the proportion of the working people aged 65–69 to the sample size and equals $\frac{180}{600}=0.3$ ie 30%

<em>b.</em>

Let p be the proportion of people aged 65–69 who is working. OECD claims that percentage working had increased. Then null and alternative hypothesis would be

$H_{0}$ : p=27%

$H_{a}$ : p>27%

z-score of the sample proportion assuming null hypothesis is:

$\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } }$ where

p(s) is the sample proportion of working people aged 65–69 (0.3)
p is the proportion assumed under null hypothesis. (0.27)
N is the sample size (600)

then z= $\frac{0.3-0.27}{\sqrt{\frac{0.27*0.73}{600} } }$ = 1.655

Since one tailed p value of 1.655 = 0.048 < 0.05, sample proportion is significantly different than the proportion assumed in null hypothesis. Therefore we reject the null hypothesis.

3 0

3 years ago

Read 2 more answers

Help with problem pls

Crazy boy [7]

The original number is .9

5 0

4 years ago

$500 principal at 12% for 0.5 years. <br> Find interest and balance.

asambeis [7]

It would $250 plus 12% use a calculator

6 0

3 years ago

(k+2) (k-1-3) : - (k+2)