Question

A circle has its center at (-2, 5) and a radius of 4 units. What is the equation of the circle? Answer choices:

Answer 1

The equation of the circle:
( x - h )² + ( y - k )² = r²;
h = - 2,  k = 5,  r = 4
Answer:
A ) ( x + 2 )² + ( y - 5 )² = 16

Answer 2

Answer:

option (a) is correct.

The equation of a circle has its center at (-2, 5) and a radius of 4 units. is $(x+2)^2+(y-5)^2=16$

Step-by-step explanation:

Given : A circle has its center at (-2, 5) and a radius of 4 units.

We have to choose the correct equation representing this given circle.

The general equation of circle with center (h , k) and radius 'r' is given by equation $(x-h)^2+(y-k)^2=r^2$

For the given circle with center at (-2, 5) and a radius of 4 units.

that is h = -2 , k = 5 and r = 4 , we have,

$(x-h)^2+(y-k)^2=r^2$ substitute, we have,

$(x-(-2))^2+(y-5)^2=(4)^2$

Simplify , we get,

$(x+2)^2+(y-5)^2=16$

Thus, option (a) is correct.

The equation of a circle has its center at (-2, 5) and a radius of 4 units. is $(x+2)^2+(y-5)^2=16$