<h2>Length = 11</h2><h2>Width = 6</h2>
The area of a rectangle is 66 ft^2:
L * W = 66
Length of the rectangle is 7 feet less than three times the width:
L = 3W-7
Substitute L in terms of W:
(3W-7) * W = 66
Factorise the equation:
3W^2 -7W = 66
3W^2 - 7W - 66 = 0
Factors of 66 =
1 66, 2 33, 3 22, 6 11
(3W + 11) (W - 6) = 0
Solve for W:
3W + 11 = 0
3W = 11
W = 3/11
W - 6 = 0
W = 0 + 6
W = 6
Using the original equation, find L:
L = 3W-7
L = 3(6)-7
L = 18-7
L = 11
L * W = 66
11 * 6 = 66
Answer:
nbvStep-by-step explanation:
The correct answer for the question that is being presented above is this one: "B.a circle with a radius of 4 in." <span>circles have an area of16 pi in2 should have a radius of 4 in.
</span>
The area of a circle is this:
Area = pi * r^2
16 pi = pi * r^2
r^2 = 16
r = 4.
Answer:
80
Step-by-step explanation:
because 8 is in tens place
so it´s value is 8*10=80
Answer:
The product 
Step-by-step explanation:
Given expression 
and 
We have to find the product of 
Consider the given expression
Multiply fractions, we have,
Cancel common factor ( b - 5 )
we have, 
Apply exponent rule,
Cancel common factor b , we have,
Thus, the product
