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yaroslaw [1]
4 years ago
5

The figure below shows rectangle ABCD:

Mathematics
2 answers:
otez555 [7]4 years ago
6 0

B would be the answer because if you were to search up a picture of alternate interior angles, it would be the same as <CAD and <ACB

kirill [66]4 years ago
6 0

Answer:

(B) ∠CAD≅∠ACB

Step-by-step explanation:

Given in the question quadrilateral ABCD is a rectangle and a table of two-column proof with missing statement for proves that the diagonals of the rectangle bisect each other.

If we want to prove that the diagonals bisects to each other, then for this  first we will prove that ΔADE≅ΔCBE. But given in the two-column proof  

∠ADB≅∠CBE , side BC= side AD .  ∠CAD ≅ACD must be  necessary for to prove that ΔADE≅ΔCBE (ASA postulate). Hence statement  ∠CAD ≅ACD can be used to fill in the blank space.

                                                 

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What is the constant in the expression?
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Answer:

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Step-by-step explanation:

A constant in an expression is the number that is not attached to any variable, and this includes the sign that comes with the number.

0.05m +12

In the expression above, m is the variable thus 0.05 is known as the coefficient of m instead of a constant. Coefficients are numbers that are multiplied to variables.

+12, which can simply be written as 12, is not multiplied to any variable and is thus the constant.

The value of the number 12 will not change no matter the value of m. The fact that the value stays the same makes it a constant.

Additional:

To learn more about constant, check out the following!

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satela [25.4K]

Answer:

<h3><u>Solution</u><u>:</u><u>-</u></h3>
  • First write the given equation

\qquad{:}\longrightarrow\sf \dfrac {5}{x+3}-\dfrac{1}{x-2}=1

\qquad{:}\longrightarrow\sf \dfrac {5 (x-2)-1 (x+3)}{(x+3)(x-2)}=1

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  • use cross multiplication method

\qquad{:}\longrightarrow\sf 5x-x-10=x^2-6x-6

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\qquad{:}\longrightarrow\sf x^2-10x+4=0

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\qquad{:}\longrightarrow\sf x=\dfrac {-b\underline{+}\sqrt {b^2-4ac}}{2a}

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\qquad{:}\longrightarrow\sf x=\dfrac {10\underline{+}\sqrt {84}}{2}

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Answer:

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