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yKpoI14uk [10]
3 years ago
14

A sports club offers an organized basketball league. A team pays $600 to join their league. In addition to paying their share of

the $600, people on the team that are not members of the sports club must pay a $25 fee to play. A team pays a total of $775. How many people on the team are not club members?
Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
8 0

Answer:7 team members

Step-by-step explanation:think of money... 25 cents times 4 is a dollar. So that means count from 600 by 25 until you get to 775

egoroff_w [7]3 years ago
4 0

Answer:

5

Step-by-step explanation:

600-775=125

25x5=125

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Answer:

-54 is a integer and rational number

Step-by-step explanation:

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3 years ago
I need some help with this
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3 years ago
The average amount of time that students use computers at a university computer center is 36 minutes with a standard deviation o
frosja888 [35]

Answer:

2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 36, \sigma = 5

The first step to solve this question is finding the proportion of students which use the computer more than 40 minutes, which is 1 subtracted by the pvalue of Z when X = 40. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{40 - 36}{5}

Z = 0.8

Z = 0.8 has a pvalue of 0.7881.

1 - 0.7881 = 0.2119

So 21.19% of the students use the computer for longer than 40 minutes.

Out of 10000

0.2119*10000 = 2119

2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.

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