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3 years ago

X = y + 3

1 answer:

8 0

I think elimination method means, add or subtract two equations in a way that it cancels a term out.

E. G.

Add the two equations,
x = y + 3
y= - 4x - 3

x+y = (y+3) + (-4x-3)
x+y = y - 4x
x=-4x
x=0

To find out Y using elimination method,
Muliply 4 to the first equation, and then subtract the second equation from the first.
4x = 4y +12
y= -4x - 3

4x-y = (4y+12) -(-4x-3)
4x-y = 4y + 4x + 15
-y = 4y + 15
-5y = 15
y = - 3

Hope this helps. Thanks

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3 years ago

A trapezoid has a height of 8 cm and bases with lengths of 14 cm and 8 cm. Tina says the area of the trapezoid is 176 cm2.

Sonbull [250]

Answer:

Step-by-step explanation:

Let's do this properly:

Area of trapezoid = average length times height.

Here,

Area = (1/2)(8 cm + 14 cm)(8 cm), or

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3 years ago

Read 2 more answers

A private and a public university are located in the same city. For the private university, 1038 alumni were surveyed and 647 sa

Snezhnost [94]

Answer:

The difference in the sample proportions is not statistically significant at 0.05 significance level.

Step-by-step explanation:

Significance level is missing, it is α=0.05

Let p(public) be the proportion of alumni of the public university who attended at least one class reunion

p(private) be the proportion of alumni of the private university who attended at least one class reunion

Hypotheses are:

$H_{0}$ : p(public) = p(private)

$H_{a}$ : p(public) ≠ p(private)

The formula for the test statistic is given as:

z= $\frac{p1-p2}{\sqrt{{p*(1-p)*(\frac{1}{n1} +\frac{1}{n2}) }}}$ where

p1 is the sample proportion of public university students who attended at least one class reunion ( $\frac{808}{1311}=0.616$ )

p2 is the sample proportion of private university students who attended at least one class reunion ( $\frac{647}{1038}=0.623$ )

p is the pool proportion of p1 and p2 ( $\frac{808+647}{1311+1038}=0.619$ )

n1 is the sample size of the alumni from public university (1311)

n2 is the sample size of the students from private university (1038)

Then z= $\frac{0.616-0.623}{\sqrt{{0.619*0.381*(\frac{1}{1311} +\frac{1}{1038}) }}}$ =-0.207

Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.

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irina1246 [14]

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