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k0ka [10]
3 years ago
15

PLEASE PLEASE HELP!!!! WILL MARK BRAINLIEST! (40 points) BOTH: what is the value of x?

Mathematics
1 answer:
Gre4nikov [31]3 years ago
3 0

Answer:

i don't know how to solve the first one but the second one is 3

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In the last election, a state representative received 52% of the votes cast. One year after the election, the representative org
butalik [34]

Answer:

The probability that more than half of the sample would vote for him is P=0.7549.

Step-by-step explanation:

With a sample size of n=300, we can approximate this to the normal distribution.

The parameters will be

\mu=p\cdot n=0.52\cdot 300=156\\\\\sigma=\sqrt{np(1-p)} =\sqrt{300\cdot 0.52(1-0.52)} =\sqrt{74.88}= 8.65

We have to calculate the probability that half or more of the sample vote for him. This is P(x>150).

To calculate this probability, first we calculate the z-value:

z=\frac{x-\mu}{\sigma}=\frac{150-156}{8.65}=\frac{-6}{8.65}=-0.69

Then

P(x>150)=P(z>-0.69)=0.7549

The probability that more than half of the sample would vote for him is P=0.7549.

5 0
3 years ago
1. A total of 498 tickets were sold for the school play. They were either adult tickets or student tickets. There were 53
arlik [135]
498-53=445
445/2=222.5
222.5+53=275.5 
so there were 222.5 student tickets sold 
to check: 275.5 + 222.5+498
6 0
3 years ago
What is 622 rounded to the nearest ten and hundred
Kamila [148]
Hundred is: 600
ten is: 620

Be sure to give me a thanks and rate me up :D
4 0
3 years ago
Read 2 more answers
I need help!!!!!! what is x&y?
Nady [450]
⭐x=7 because
10x+65=135
10x=70
x=7
28=4y-4
32=4y
⭐y=8
I hope this helps
8 0
3 years ago
A research firm wants to compute an interval estimate with 90% confidence for the mean time to complete an employment test. Assu
gavmur [86]

Answer:

b. 98

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

In this problem, we have that:

M = 0.5, \sigma = 3

M = z*\frac{\sigma}{\sqrt{n}}

0.5 = 1.645*\frac{3}{\sqrt{n}}

0.5\sqrt{n} = 4.935

\sqrt{n} = 9.87

n = 97.42

So a sample of at least 98 is required.

The correct answer is:

b. 98

5 0
3 years ago
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