Answer:Hope this helps :D
Explanation:
Cu = 27, S = 16 and O = 25.92
relative formula mass = 27 + 16 + (5.4x4.8) = 286.216
only one aluminum atom of relative atomic mass
64 % Cu = 100 x 64 / 160
x = 1036.8
How thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.
<h3>Density of the Neutron star</h3>
Density
ρ = m / V
Where:
ρ= density
m = mass of the planet 5.98 10²⁴ km
V =volume of the spherical layer
Volume of a sphere
Volume = 4/3 π r³
Mass = 1.5 = 1.5 1,991 10³⁰
Mass= 2.99 10³⁰ kg
Density:
ρ = 2.99 10³⁰ / [4/3 π (10 10³)³]
ρ is = 7.13 10 17 kg / m³
V = 5.98 10²⁴ / 7.13 10¹⁷
V = 8,387 10⁶ m³
Thickness of the layer
V = 4π r² e
e = V / 4π r
e = 8,387 10⁶ / [4π (10 10³)²]
e = 6.67 10⁻³ m
Inconclusion how thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.
Learn more about Density of the Neutron star here:brainly.com/question/15700804
Answer:
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Explanation:
- <em>A </em><em>pag-aararo</em>
- <em>D.</em><em> </em><em> pagiging katulong sa ibang bansa</em>
- <em>D </em><em>.</em><em>pag </em><em>gawa </em><em>Ng </em><em>kasangkapang </em><em>elektroniks</em>
- <em>A.</em><em> </em><em>komunismo</em>
- <em>Saudi </em><em>Arabia</em>
<h2><em>hope</em><em> it</em><em> helps</em><em>!</em></h2>
Answer:
B- is likely going to be your answer.
