Question

Answer asap please

Answer 1

Answer:

(0,1) and (-2,9)

Step-by-step explanation:

A point (x,y) lies on the graph of f(x) = $(\frac{1}{3} )^{x}$ if it satisfies the condition y = $(\frac{1}{3} )^{x}$

(0,1):

        x = 0 and y = 1.

This point satisfies the required condition as

        $(\frac{1}{3} )^{0}$ = 1

Hence, this point is on the graph of f(x) = $(\frac{1}{3} )^{x}$

(3,27):

        x = 3 and y = 27.

This point doesn't satisfy the required condition as

        $(\frac{1}{3} )^{3}$ = $\frac{1}{27}$ ≠ 27

Hence, this point is not on the graph of f(x) = $(\frac{1}{3} )^{x}$

(-2,9):

        x = -2 and y = 9.

This point satisfies the required condition as

        $(\frac{1}{3} )^{-2}$ = $3^{2}$ = 9

Hence, this point is on the graph of f(x) = $(\frac{1}{3} )^{x}$

(-1,$-\frac{1}{3}$):

        x = -1 and y = $-\frac{1}{3}$.

This point satisfies the required condition as

        y = $(\frac{1}{3} )^{-1}$ = $3^{1}$ = 3 ≠ $-\frac{1}{3}$

Hence, this point is not on the graph of f(x) = $(\frac{1}{3} )^{x}$