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a_sh-v [17]
3 years ago
8

Hox genes determine an animal's.

Biology
2 answers:
allsm [11]3 years ago
4 0
Hox genes would be a group of related genes that control the body plan. :) So, .B
Sholpan [36]3 years ago
3 0
Body plan.

Hope this helps!

-Payshence xoxo
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Name the 5 Steps in the Scientific Method
Georgia [21]

Answer:

Explanation:

What question could you ask, and can your data answer it? What experiment could we do that could? What tools are you using to collect data? What would happen if we changed/ improved the tools?

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Question 18 of 32 What kind(s) of cells can develop from unipotent stem cells? A. Only cells that are closely related to the ori
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A. Only cells that are closely related to the original stem cell

Explanation:

Hope this helps :)

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True or false. The absence of a trait cannot be used as a synapomorphy in phylogenetic analysis
kolbaska11 [484]

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False

Explanation:

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The absence of a trait can be used as a synapomorphy in phylogenetic analysis. For example, the loss of a trait, such as the loss of legs in snakes, can be a valuable synapomorphy for a clade.

4 0
3 years ago
Changing the state of matter is an example of a chemical change
pshichka [43]

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false

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4 0
3 years ago
Read 2 more answers
In a population of tree frogs, the allele that causes yellow eyes (Y) is dominant over the allele that causes orange eyes (y). I
polet [3.4K]

Hardy-Weinberg Principle

Genotype frequency equation

 p^{2} +2pq +  q^{2} = 1

Where p² is the freq of homo dominant genotype, 2pq is the freq of heterozygous genotype and q² is the freq of homo recessive genotype.

Allele frequency equation

p + q = 1

Where p is the frequency of dominant alleles and q is the frequency of recessive alleles.

Yellow eyes in the frog offspring is a phenotype (physical trait) that would be a expressed by a geneotype (YY or Yy). This frequency, 0.85 includes: p² + 2pq

0.85 + q² = 1

q² = 0.15

p = \sqrt{0.15} 

Then p + \sqrt{0.15}  = 1

1 - \sqrt{0.15} = p

p = 0.613

61%



7 0
3 years ago
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