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fiasKO [112]
3 years ago
6

(07.02 MC) In ΔJKL, solve for x. (4 points) Triangle JKL where angle K is a right angle. KL measures 34. JK measures x. Angle J

measures 27 degrees.

Mathematics
2 answers:
Anuta_ua [19.1K]3 years ago
7 0

Answer:

66.73

Step-by-step explanation:

Elenna [48]3 years ago
5 0

Answer:

66.7  

Step-by-step explanation:

  tan27 = 34/x

0.5095 = 34/x

          x = 34/0.5095

             = 66.7

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Pls help, needed asap. Thank you and can you explain, im having troubles
Step2247 [10]

Step-by-step explanation:

(I'll be adding more answers to this answer soon!)

Alright, let's start off with the first question. :)

So, the entire length of AC is 60.

AB + BC = AC, as you can infer from the diagram.

We know that AB is 2x + 8, and AC is 3x + 7.

So,

2x + 8 + 3x + 7 = 60.

Now, we can simply evaluate for x:

Combine the like terms to get 5x + 15 = 60

Subtract 15 to get 5x = 45

Divide by 5 to get the first question's answer as x = 5 :)

------

Time for the second question!

AD is a straight angle. If an angle is straight, it measures 180 degrees. So,

AD = 180

From the diagram, we can tell that x+17 and 5x+13 add up to 180.

x + 17 + 5x + 13 = 180

Now, we can simply solve for x!

6x + 30 = 180

6x = 180 - 30 = 150

x = 150 / 6 = 25

So, we get x = 25 as the answer to the second question! :)

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