Answer:
72.4%
Step-by-step explanation:
The probability of A occurring given that B occurs = the probability of both A and B / the probability of B
P(A|B) = P(A∩B) / P(B)
This can be rearranged as:
P(A∩B) = P(B) P(A|B)
In this case:
A = biased coin is chosen
~A = fair coin is chosen
B = 4 heads then 1 tail
First, let's find P(A∩B).
P(A∩B) = P(B) P(A|B)
P(A∩B) = ½ × ₅C₄ (⅘)⁴ (⅕)¹
P(A∩B) = 0.2048
Next, find P(~A∩B).
P(~A∩B) = P(B) P(~A|B)
P(~A∩B) = ½ × ₅C₄ (½)⁴ (½)¹
P(~A∩B) = 0.078125
Therefore, the probability that the coin is biased is:
P = P(A∩B) / (P(A∩B) + P(~A∩B))
P = 0.2048 / (0.2048 + 0.078125)
P = 0.723866749
The probability is approximately 72.4%.
The characteristic of the repeating shapes in a tessellation is that shapes cannot have spaces between them.
<h3>What is tessellation ?</h3>
When we talk about tessellation, our minds go to a situation in which many shapes especially polygons are packed together without spaces between them.
Thus, the characteristic of the repeating shapes in a tessellation is that shapes cannot have spaces between them.
Learn more about tessellation: brainly.com/question/3294818
#SPJ1
hi im new how do i privatly chat on here?
