Simplify the expression. 2.5 – 3.1 – 3.86 + 2.7

What's the value of X

ss7ja [257]

Since the triangle is isosceles we know that angle a is equal to angle c.

8y-7=73

8y=80

y=10

We also know that the sum of the interior angles in any triangle is 180 degrees.

73+73+6x+4=180

150+6x=180

6x=30

x=5

3 0

3 years ago

What is (f−g)(x)? f(x)=x^4−x^2+9 g(x)=x^3+3x^2+12 (f−g)(x)=

wlad13 [49]

Answer:

x^4 -x^3 -4x^2-3

Step-by-step explanation:

f(x)=x^4−x^2+9

g(x)=x^3+3x^2+12

(f−g)(x)= x^4−x^2+9 - (x^3+3x^2+12)

Distribute the minus sign

(f−g)(x)= x^4−x^2+9 - x^3-3x^2-12

I like to line them up vertically

x^4 −x^2+9

- x^3 -3x^2-12

---------------------------

x^4 -x^3 -4x^2-3

7 0

3 years ago

Order the following from least to greatest. 3.1, 118%, 5/12, 0.06, 2/7

photoshop1234 [79]

Answer:

0.06, 2/7, 5/12, 118%, 3.1

Step-by-step explanation:

7 0

3 years ago

Professor Jennings claims that only 35% of the students at Flora College work while attending school. Dean Renata thinks that th

lisov135 [29]

Answer:

$z=\frac{0.462 -0.35}{\sqrt{\frac{0.35(1-0.35)}{78}}}=2.074$

Now we can calculate the p value with this probability:

$p_v =P(z>2.074)=0.019$

If we use a significance level os 0.05 we see that the p value is lower than the significance level so then we can conclude that the true proportion of students with jobs is higher than 0.35 for this case. If we decrease the significance level to 1% the result changes otherwise not.

Step-by-step explanation:

Information given

n=78 represent the random sample taken

X=36 represent the students with jobs

$\hat p=\frac{36}{78}=0.462$ estimated proportion of students with jobs

$p_o=0.35$ is the value that we want to test

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the proportion of students with jobs is higher than 0.35, the system of hypothesis are:

Null hypothesis: $p \leq 0.35$

Alternative hypothesis: $p > 0.35$

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info we got:

$z=\frac{0.462 -0.35}{\sqrt{\frac{0.35(1-0.35)}{78}}}=2.074$

Now we can calculate the p value with this probability:

$p_v =P(z>2.074)=0.019$

If we use a significance level os 0.05 we see that the p value is lower than the significance level so then we can conclude that the true proportion of students with jobs is higher than 0.35 for this case. If we decrease the significance level to 1% the result changes otherwise not.

5 0

4 years ago

X -9 -5 -1 3 Y - 2 0 2 4 What is the slope of the line?

Mekhanik [1.2K]

ok done. Thank to me :>

5 0

2 years ago

Simplify the expression. 2.5 – 3.1 – 3.86 + 2.7 – 4.01