Answer:
0.3991
Step-by-step explanation:
Given that the weights of the fish in a certain lake are normally distributed with a mean of 18 lb and a standard deviation of 18 .
we know that when a sample is taken mean would be the same but std error would vary
when a sample of size 15 is taken we have
![n=15](https://tex.z-dn.net/?f=n%3D15)
Standard error of sample = ![\frac{\sigma}{\sqrt{n} } \\=2.065](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%20%7D%20%5C%5C%3D2.065)
the probability that the mean weight will be between 16.6 and 21.6 lb
![=P(16.6](https://tex.z-dn.net/?f=%3DP%2816.6%3Cx%3C21.6%29%5C%5C%3DP%28-0.30%3Cz%3C0.77%29%5C%5C%3D0.3991)
So we get the required probability as
0.3991
Answer:
prefixes
Step-by-step explanation:
The exact response will depend a lot on what you learned in your manual and the terms used in it, but the metric system is all based on the base of 10, like the numbers system you use every day.
Unlike the US/Imperial system where there's no clear relation between an inch, a yard and a mile for example, in the metric system everything is related by the factor 10 somehow.
The unit multiplier is also used as a prefix to identify measurements. Like for meter...
10 meters = 1 decameter
100 meters = 1 hectometer
1000 meters = 1 kilometer
and so on.
The elevation goes from 0 ft to -440 ft in 20 seconds.
Divide the feet by the seconds.
(-440 ft)/(20 sec) = -22 ft/sec
Answer:
2.300cb squred divide by 4 ull get .575
Step-by-step explanation: