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Keith_Richards [23]
4 years ago
15

A nest if ants initially contains 500 individuals. The population is increasing by 12% each week. How many ants will there be af

ter 10 weeks and 20 weeks?
Mathematics
1 answer:
allochka39001 [22]4 years ago
8 0
Based on the given values above, here is the solution to find if how many ants there will be after 10 weeks and 20 weeks.
Since the population increases by 12%. we need to get 12% of the population every week.
500 x .12 = 60.
1st week = 560
2nd week = 627.2
3rd week = 702. 46
4th week = 786.76
5th week = 881. 17
6th week = 986.91
7th week= 1,105.34
8th week= 1,237.98
9th week= 1, 386.54
10th week = 1, 552.92
11th week = 1,739.27
12th week = 1,947.98
13th week= 2,181.74
14th week=2, 443.55
15th week = 2,736.76
16th week = 3, 065. 17
17th week = 3,432.99
18th week= 3,844.95
19th week= 4,306.34
20th week = 4,823.10
Therefore, after 10 weeks, there will be 1,553 ants and after 20 weeks, there will be 4,823 ants.
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andrew-mc [135]

The value of expression 15/16 *9.1/5 is 69/8.

Given an expression being 15/16* 9.1/5.

We are required to solve the expression and find the value of the expression.

Expression is combination of numbers, symbols, coefficients, fractions, determinants, indeterminants but not mostly found in equal to form.

The expression is 15/16 *9.1/5.

9.1/5 is given in mixed fraction form so we have to first simplify it to a simple form.

Fraction is a combination of two numbers, one exists above the division sign and one below the division sign.

9.1/5=(5*9+1)/5=46/5

Now put the value of 9.1/5 in the given expression.

=15/16 * 46/5

=690/80

=69/8

Hence the value of expression 15/16 *9.1/5 is 69/8.

Learn more about expressions at brainly.com/question/723406

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