There are 2 x’s so it’s 2x^2 + 9x because 2x4 is 8 + 1 x and then + 4 because you connect like terms so it would be 2x^2+9x+4
Primary equation: A(x)= (5y)(3X)
Secondary equation: 5y+3X=1000
y=200-(3X)/5
A(x)=3X(1000-3X)
A(x)=3000X-9X²
Now, find the derivative of A(x) to find the max... here's the work for that, or you could guess and check.
A'(x)=3000-18X
Set derivative equal to 0
0=3000-18X
166.6666666=X
Now test the intervals
(0,166.6666) (166.66666, 1000)
1st derivative is + 1st derivative is -
Plug the X value back into the secondary equation
5y+3(166.666666)=1000
5Y=500
Y=5
Answer:
X= 166.6666666666
Y=5
Please note, this is entry level calculus, and your teacher may expect you to use a different, longer route such as guess and check.
128=11x+18.
-18. -18.
110=11x
————
11. 11
X=10
Answer:
Yes, it is a very effective test, having almost a 100% detection rate you wouldn't need much to improve upon except testing multiple times.
