How do I solve this problem
1 answer:
Hi there!
Since, The length of th' tangents drawn from an external point to a circle are equal.
Therefore, we draw following conclusions :-
• CF = EC = 6 cm
• BE = DB = 16 cm
• AD = FA = 12 cm
Now,
According to th' question, Perimeter of ΔΑΒC :-
AB + BC + AC
⇒ AD + DB + BE + EC + CF + FA
⇒ 12 cm + 16 cm + 16 cm + 6 cm + 6 cm + 12 cm = 68 cm
Hence,
The Perimeter of ΔΑΒC is 68 cm
~ Hope it helps!
Since, The length of th' tangents drawn from an external point to a circle are equal.
Therefore, we draw following conclusions :-
• CF = EC = 6 cm
• BE = DB = 16 cm
• AD = FA = 12 cm
Now,
According to th' question, Perimeter of ΔΑΒC :-
AB + BC + AC
⇒ AD + DB + BE + EC + CF + FA
⇒ 12 cm + 16 cm + 16 cm + 6 cm + 6 cm + 12 cm = 68 cm
Hence,
The Perimeter of ΔΑΒC is 68 cm
~ Hope it helps!
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Answer:
Parallel
Step-by-step explanation:
-y₁ + y₂\-x₁ + x₂ = m
Both <em>rate</em><em> </em><em>of</em><em> </em><em>changes</em><em> </em>[<em>slopes</em>] result in <em>three</em>, therefore both lines are parallel.
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