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Ostrovityanka [42]
3 years ago
12

How many litres of milk can be put in six hemispherical bowl each of diameter 35cm​

Mathematics
1 answer:
Lesechka [4]3 years ago
3 0

Answer:

Approximately 67.348 litres can be put in six hemispherical bowl with a diameter of 35 centimetres.

Step-by-step explanation:

The volume of a hemisphere (V), measured in cubic centimetres, is obtained from this formula:

V = \frac{2\pi}{3}\cdot R^{3}

Where R is the radius of the hemisphere, measured in centimetres.

We know that radius is the half of the diameter (D), measured in centimetres, then:

R = 0.5\cdot D

(D = 35\,cm)

R = 0.5\cdot (35\,cm)

R = 17.5\,cm

Now, we get the volume of each hemispherical bowl:

V = \frac{2\pi}{3} \cdot (17.5\,cm)^{3}

V \approx 11224.649\,cm^{3}

The total volume of six hemispherical bowl is:

V_{T} = 6\cdot V

V_{T}= 6\cdot (11224.649\,cm^{3})

V_{T} = 67347.894\,cm^{3}

From Physics we know that 1 litre equals 1000 cubic centimetres. Then:

V_{T} = 67.348\,L

Approximately 67.348 litres can be put in six hemispherical bowl with a diameter of 35 centimetres.

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which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1​
lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. y=\sec x

B. y= \tan x

C. y= \cot x

D. y= \csc x

Answer:

A. y=\sec x

D. y=\csc x

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: y=\sec x

We know that, the \sec x=\frac{1}{\cos x}

The range of \cos x is from -1 to 1 given as [-1, 1]. So,

|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1

Therefore, on removing the absolute sign, we rewrite the secant function as:

\sec x\leq -1\ or\ \sec x\geq 1\\

Therefore, the range of y=\sec x is all real numbers greater than or equal to 1 or less than or equal to-1​.

Choice B: y= \tan x

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: y= \cot x

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: y=\csc x

We know that, the \csc x=\frac{1}{\sin x}

The range of \sin x is from -1 to 1 given as [-1, 1]. So,

|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

\csc x\leq -1\ or\ \csc x\geq 1\\

Therefore, the range of y=\csc x is all real numbers greater than or equal to 1 or less than or equal to-1​.

6 0
3 years ago
What kind of solution is -4x-4=-7(x+4) ?
natima [27]

~ Simplifying

-4x + -4 = -7(x + 4)

~ Reorder the terms:

-4 + -4x = -7(x + 4)

~ Reorder the terms:

-4 + -4x = -7(4 + x)

-4 + -4x = (4 * -7 + x * -7)

-4 + -4x = (-28 + -7x)

~ Solving

-4 + -4x = -28 + -7x

~ Solving for variable 'x'.

~ Move all terms containing x to the left, all other terms to the right.

~ Add '7x' to each side of the equation.

-4 + -4x + 7x = -28 + -7x + 7x

~ Combine like terms: -4x + 7x = 3x

-4 + 3x = -28 + -7x + 7x

~ Combine like terms: -7x + 7x = 0

-4 + 3x = -28 + 0

-4 + 3x = -28

~ Add '4' to each side of the equation.

-4 + 4 + 3x = -28 + 4

~ Combine like terms: -4 + 4 = 0

0 + 3x = -28 + 4

3x = -28 + 4

~ Combine like terms: -28 + 4 = -24

3x = -24

~ Divide each side by '3'.

x = -8

~ Simplifying

x = -8

8 0
3 years ago
Read 2 more answers
1 point
photoshop1234 [79]

Answer:

 b

Step-by-step explanation:

done it

5 0
3 years ago
A carton measuring 72 cm by 48 cm by 75 cm was packed with cyndrical tins of radius 6 cm and height 15 cm standing upright.How m
Ierofanga [76]

Answer:

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Step-by-step explanation:

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3 years ago
Click on the correct answer.
Galina-37 [17]

Answer:

A, $1.08

Step-by-step explanation:

1.20 / 90 = 1.08

use a calculator

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