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3 years ago

11

write a division problem that has a 3 digit dividend and divisor between 10 and 20 show how to solve it by you real quick pictur

e

1 answer:

melisa1 [442]3 years ago

8 0

IDK how to do a picture but a problem is 242/11
11 goes into 24 twice, leaving 2, 11 goes into 22 twice. answer, 2

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Evaluate a+b+c when a=4.035, b= -17, and c=12.3

Aleksandr [31]

The answer will probably be -0.665

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3 years ago

Use numbers in part a

Zina [86]

Answer: 3.568 ⋅ $10x^{8\\}$

Step-by-step explanation:

If you have to evaluate it then thats your answer if not hit me back ASAP

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3 years ago

At a certain time of day, a 5 foot tall man has a 7.5 foot shadow. if a tree is 20 feet tall, what is the length of the shadow o

bezimeni [28]

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7 0

4 years ago

Let U= U= Universal set ={0, 1, 2, 3, 4, 5, 6, 7, 8, 9}={0, 1, 2, 3, 4, 5, 6, 7, 8, 9} , A={1, 3, 4, 5, 7, 9} A={1, 3, 4, 5, 7,

blagie [28]

Answer:

a) $A' = [0,2,6,8]$

b) $(AUB)' = [0,2,6]$

c) $(AUB')' = [9]$

d) A∩B′ $= [3,5,9]$

Step-by-step explanation:

Assuming this problem: "Let U= U= Universal set ={0, 1, 2, 3, 4, 5, 6, 7, 8, 9} , A={1, 3, 4, 5, 7, 9} , and B={1, 4, 7, 8} . List the elemetns of the following sets in the increasing order: a) A′= b) (A∪B)′={ , , }} c) (A∪B′)′={ }} d) A∩B′={ , , }}"

Part a

For this case we just need to find the elements in the universal set that are not in A. And we see that:

$A' = [0,2,6,8]$

And that represent the complement for A

Part b

For this case we need to find first the Union AUB who are the elements on A or B without repetition and we got:

$AUB = [1,3,4,5,7,8,9]$

And now the complement for (AUB)' are the elements that are not in AUB but are on the universal set and we got:

$(AUB)' = [0,2,6]$

Part c

For this case we need to find B' who are the elements on the universal set that are not in B

$B' = [0,2,3,5,6,9]$

Then we can find the union between AUB' and we got:

$AUB' = [0,1,2,3,4,5,6,7,9]$

And then the complment is just:

$(AUB')' = [9]$

Part d

For this case we just need to see the elements in common between A and B' and we got:

A∩B′ $= [3,5,9]$

6 0

4 years ago

******ANSWER ASAP PLEASE******

Lemur [1.5K]

(1/4)^-2 - (5^0 x 2) x 1^-1 =

(4/1)^2 - (1 x 2) x 1 = 16-2 = 14

If you raise something to the power of -2, swap numerator and denominator and remove the minus.

So (1/4)^-2 = 4^2 = 16

Also 1^-1 is just 1, not -1.

8 0

3 years ago